摘要:1120 14. 15.40 16.12
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观察不等式:
•1≥
•
,
(1+
)≥
(
+
),
(1+
+
)≥
(
+
+
),…,由此猜测第n个不等式为
•(1+
+…+
)≥
•(
+…+
)
•(1+
+…+
)≥
•(
+…+
).
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1 |
2 |
1 |
1 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
2 |
1 |
2 |
1 |
4 |
1 |
4 |
1 |
3 |
1 |
5 |
1 |
3 |
1 |
2 |
1 |
4 |
1 |
6 |
1 |
n+1 |
1 |
3 |
1 |
2n-1 |
1 |
n |
1 |
2 |
1 |
2n |
1 |
n+1 |
1 |
3 |
1 |
2n-1 |
1 |
n |
1 |
2 |
1 |
2n |
化简:(1+2-
)(1+2-
)(1+2-
)(1+2-
)(1+2-
),结果是( )
1 |
32 |
1 |
16 |
1 |
8 |
1 |
4 |
1 |
2 |
A、
| ||||
B、(1+2-
| ||||
C、1-2-
| ||||
D、
|