摘要: 把曲线ycosx+2y-1=0先沿x轴向右平移个单位.再沿y轴向下平移1个单位.得到的曲线方程是
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把曲线ycosx+2y-1=0先沿x轴向右平移个单位,再沿y轴向下平移1个单位,得到的曲线方程是( )
A.(1-y)sinx+2y-3=0 B.(y-1)sinx+2y-3=0
C.( y+1)sinx+2y+1=0 D.-(y+1)sinx+2y+1=0
查看习题详情和答案>>把曲线yCosx+2y-1=0先沿x轴向右平移个单位,再沿y轴向下平移1个单位,得到的曲线方程是( )
A.(1-y)sinx+2y-3=0
B. (y-1)sinx+2y-3=0
C. (y+1)sinx+2y+1=0
D.- (y+1)sinx+2y+1=0
把曲线ycosx+2y-1=0先沿x轴向右平移个单位,再沿y轴向下平移1个单位,得到的曲线方程是( )
A.(1-y)sinx+2y-3=0 B.(y-1)sinx+2y-3=0
C.(y+1)sinx+2y+1=0 D.-(y+1)sinx+2y+1=0
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