摘要:已知a>0.函数f(x)=.x∈.设0<x1<.记曲线y=f(x)在点M(x1.f(x1))处的切线为l.(Ⅰ)求l的方程,(Ⅱ)设l与x轴交点为(x2.0).证明:
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(20)已知a>0,函数f(x)=,x∈(0,+∞).设0<x1<,设曲线y=f(x)在
点M(x1,f(x1))处的切线为l.
(Ⅰ)求l的方程;
(Ⅱ)设l与x轴交点为(x2,0).证明:
(i)0<x2≤;
(ii)若x1<,则x1<x2<.
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