摘要:当动点P在射线BA的右侧时.结论是∠PBD=∠PAC+∠APB .(b)当动点P在射线BA上.结论是∠PBD =∠PAC +∠APB .或∠PAC =∠PBD +∠APB 或 ∠APB = 0°.∠PAC =∠PBD.(c) 当动点P在射线BA的左侧时.

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