摘要: (1)解法一:如图9-1延长BP交直线AC于点E ∵ AC∥BD , ∴ ∠PEA = ∠PBD . ∵ ∠APB = ∠PAE + ∠PEA , ∴ ∠APB = ∠PAC + ∠PBD .

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