摘要:得EH⊥平面ABCD.且EH. 作HM⊥BD于M.连结EM.由三垂线定理可得EM⊥BD.故∠EMH为二面角E―BD―F的平面角.故∠EMH=600.∵ Rt△HBM∽Rt△DBF,
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(1)求四棱锥P-ABCD的体积;
(2)求证:AP∥GH.
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(I)求证:BD丄AA1;
(II)若四边形ACC1A1是菱形,且∠A1AC=60°,求四棱柱 ABCD-A1B1C1D1 的体积.