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若奇函数y=f(x)(x∈R)满足f(2)=1,f(x+2)=f(x)+f(2),则f(5)等于
A.0
B.1
C.
D.5
函数f(x)的定义域为R,且满足:f(x)是偶函数,f(x-1)是奇函数,若f(0.5)=9,则f(8.5)等于
A.-9
B.9
C.-3
D.0