摘要:计算: (1)3+4×(-)-23+(-)2; (2)22-23×0.25+2 0060+|-3-1|; (3)99×(-7); 3-(-5)]. 答案:(1)-6,-699,(4)-. 提示:根据法则进行有理数的混合运算.
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观察下列各式:
13+23=
×4×9=
×22×32;
13+23+33=36=
×9×16=
×32×42;
13+23+33+43=100=
×16×25=
×42×52;
(1)计算:13+23+33+43+53的值;
(2)计算:13+23+33+43+…+103的值;
(3)猜想:13+23+33+43+…+n3的值.
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13+23=
| 1 |
| 4 |
| 1 |
| 4 |
13+23+33=36=
| 1 |
| 4 |
| 1 |
| 4 |
13+23+33+43=100=
| 1 |
| 4 |
| 1 |
| 4 |
(1)计算:13+23+33+43+53的值;
(2)计算:13+23+33+43+…+103的值;
(3)猜想:13+23+33+43+…+n3的值.
阅读:计算:(-
)÷(
-
+
-
)
解法1:原式=-
=(-
)÷(
-
)=-
×3=-
解法2:原式的倒数为:(
-
+
-
)÷(-
)=(
-
+
-
)×(-30)=-20+3-5+12=-10
请阅读上述材料,选择合适的方法计算:(-
)÷(
-
+
-
).
查看习题详情和答案>>
| 1 |
| 30 |
| 2 |
| 3 |
| 1 |
| 10 |
| 1 |
| 6 |
| 2 |
| 5 |
解法1:原式=-
| 1 |
| 10 |
| 1 |
| 30 |
| 5 |
| 6 |
| 1 |
| 2 |
| 1 |
| 30 |
| 1 |
| 10 |
解法2:原式的倒数为:(
| 2 |
| 3 |
| 1 |
| 10 |
| 1 |
| 6 |
| 2 |
| 5 |
| 1 |
| 30 |
| 2 |
| 3 |
| 1 |
| 10 |
| 1 |
| 6 |
| 2 |
| 5 |
请阅读上述材料,选择合适的方法计算:(-
| 1 |
| 42 |
| 1 |
| 6 |
| 3 |
| 14 |
| 2 |
| 3 |
| 2 |
| 7 |