摘要:22.解:(1)四边形是正方形.∴BC=OA=OC=4. 为中点.轴.. 且-------而. --------------- (2) . 设直线的解析式为 .则 折痕所在直线解析式为·········································································· (3).......... 本资料由 提供!

网址:http://m.1010jiajiao.com/timu3_id_469610[举报]

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网