摘要: (1)从图中可知.60mL Ba(OH)2溶液恰好中和10mL混酸.则: [H+]×10 = ×60.解得:[H+] = 0.3 设[H2SO4]为C1.[HCl]为C2.从图中可知.20mL Ba(OH)2恰好跟H2SO4完全反应.则:0.025×20 = C1×10.解得C1 = 0.05.C2 = 0.3-0.05×2 = 0.2. 2正好将混酸中H2SO4中和完全.所以混酸中只有HCl.则[H+] = .pH = -lg6.710-2 = 1.17.B点:混酸中的HCl被加入的2溶液中和了一部分. 则[H+] = , pH = -lg210-2 = 1.7.

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