摘要:22. 化学反应N2+3H2 = 2NH3的能量变化如下图所示.该反应的热化学方程式是 A.N2(g)+3H2(g) = 2NH3 (l),⊿H = 2(a-b-c)kJ·mol-1 B.N2(g)+3H2(g) = 2NH3(g) ,⊿H = 2(b-a)kJ·mol-1 C.N2(g)+H2(g) = NH3(l) ,⊿H = (b+c-a)kJ·mol-1[来源:Z&xx&] D.N2(g)+H2(g) =NH3(g) ,⊿H = (a+b)kJ·mol-1

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