题目内容
化学反应N2+3H2===2NH3的能量变化如下图所示,该反应的热化学方程式是
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A.N2(g)+3H2(g)===2NH3(l) ΔH=2(a-b-c)kJ/mol
B.N2(g)+3H2(g)===2NH3(g) ΔH=2(b-a)kJ/mol
C.1/2N2(g)+3/2H2(g)===NH3(l) ΔH=(b+c-a)kJ/mol
D.1/2N2(g)+3/2H2(g)===NH3(g) ΔH=(a+b)kJ/mol
B.N2(g)+3H2(g)===2NH3(g) ΔH=2(b-a)kJ/mol
C.1/2N2(g)+3/2H2(g)===NH3(l) ΔH=(b+c-a)kJ/mol
D.1/2N2(g)+3/2H2(g)===NH3(g) ΔH=(a+b)kJ/mol
A
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