摘要:解:(1)∵当开关S1闭合.S2.S3断开时.两电阻串联,R总=R1+R2=5Ω------- ∴U=IR总=0.6A×5Ω=3V------------------------------------------ (2)∵当开关S1.S2.S3都闭合时,R1被短路.R2与L并联.直接接入电源, ∴UL=U2=U=3V,-------------------------------------------------- I2===1A;----------------------------------------------- ∴IL= I总-I2=0.5A------------------------------------------------ ∴Ρ=IL UL=0.5A×3V=1.5W----------------------------------------- (3)∵W2= I2 U2t=1A×3V×60s=180J,--------------------------------

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