题目内容
如图所示,线圈abcd的面积是0.05m2,共100匝,线圈电阻忽略不计,外接电阻R=10Ω,匀强磁场的磁感应强度为B=
T,当线圈以
(rad/s)的角速度匀速旋转时,求:
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408241800439898309.jpg)
(1)求线圈中感应电动势的最大值
(2)若从线圈处于中性面开始计时,写出线圈中感应电动势的瞬时值表达式.
(3)电路中电压表和电流表的示数各是多少?
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180043490365.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180043739525.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408241800439898309.jpg)
(1)求线圈中感应电动势的最大值
(2)若从线圈处于中性面开始计时,写出线圈中感应电动势的瞬时值表达式.
(3)电路中电压表和电流表的示数各是多少?
(1)50V(2)
(V)(3)
V ,
A
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180044036711.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180044254440.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180044270447.png)
试题分析:(1)根据公式
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180044488782.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408241800447531492.png)
(2)中性面时瞬时电压为0,所以
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180044036711.png)
(3)由闭合电路的欧姆定律得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180045221624.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180045440657.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180045658698.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180045877876.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824180046095900.png)
点评:对于交流电表,显示的是交流电的有效值.瞬时值表达式要注意计时起点,不同的计时起点表达式的初相位不同.
![](http://thumb.zyjl.cn/images/loading.gif)
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