题目内容
如图所示,某人用155N的力沿斜面方向向上推一个放在粗糙斜面上的物体,物体重200N,斜面倾角为30o,物体与斜面间动摩擦因数μ=
,则物体受到的摩擦力是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241441151802317.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824144115117436.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241441151802317.png)
A.![]() |
B.50N |
C.55N |
D.75N |
C
物体与斜面的最大静摩擦力为
N,重力沿斜面向下的分力为100N,由于155N<100N+75N,所以物体只能相对斜面静止,静摩擦力为155N-100N=55N,C对;
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241441154291476.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目