ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ä³ÊµÑéС×éÀûÓÃÈçͼ¼×ËùʾµÄʵÑé×°ÖÃÀ´ÑéÖ¤¹³ÂëºÍ»¬¿éËù×é³ÉµÄϵͳ»úеÄÜÊغ㡣ͼÒÒËùʾÊÇÓÃÓα꿨³ß²âÁ¿ÕÚ¹âÌõµÄ¿í¶È£¬Æä¶ÁÊýd=_______cm£»ÊµÑéʱ½«»¬¿é´ÓͼʾλÖÃÓɾ²Ö¹ÊÍ·Å£¬ÓÉÊý×Ö¼ÆʱÆ÷¶Á³öÕÚ¹âÌõͨ¹ý¹âµçÃŵÄʱ¼ä¦¤t=1.2¡Á10-2s£¬Ôò»¬¿é¾­¹ý¹âµçÃÅʱµÄ˲ʱËÙ¶ÈΪ________m/s¡£ÔÚ±¾ÊµÑéÖУ¬ÎªÁËÑé֤ϵͳµÄ»úеÄÜÊÇ·ñÊغ㣬Ðè殲âÁ¿µÄÎïÀíÁ¿³ýÁËd¡¢¦¤tºÍ¹³ÂëµÄÖÊÁ¿Í⣬»¹ÐèÒª²âÁ¿________ºÍ__________.

¡¾´ð°¸¡¿ 0.52cm 0.43m »¬¿éÉÏÕÚ¹âÌõµÄ³õʼλÖõ½¹âµçÃŵľàÀë »¬¿éµÄÖÊÁ¿

¡¾½âÎö¡¿ÕÚ¹âÌõµÄ¿í¶Èd=0.5cm+0.1mm¡Á2=0.52cm£»»¬¿é¾­¹ý¹âµçÃÅʱµÄ˲ʱËÙ¶ÈΪ

ΪÁËÑé֤ϵͳµÄ»úеÄÜÊÇ·ñÊغ㣬¼´ÅжÏϵͳ¶¯ÄܵÄÔö¼ÓÁ¿ÓëϵͳÖØÁ¦ÊÆÄܵļõСÁ¿ÊÇ·ñÊغ㣬ËùÒÔ»¹ÐèÒª²âÁ¿µÄÎïÀíÁ¿ÓУº»¬¿éÉÏÕÚ¹âÌõµÄ³õʼλÖõ½¹âµçÃŵľàÀë¡¢»¬¿éµÄÖÊÁ¿£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø