ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬¿ÉÒÔÊÓΪÖʵãµÄС½ðÊô¿éAµÄÖÊÁ¿Îªm1=1kg£¬·ÅÔÚºñ¶È²»¼ÆµÄ³¤Ä¾°åAµÄÓҶˣ¬Ä¾°å³¤L=2m¡¢ÖÊÁ¿m2=2kg£¬AÓëBÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì1=0.1£¬A¡¢BÓëˮƽÃæÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý¾ùΪ¦Ì2=0.5£®¿ªÊ¼Ê±AºÍB¾ù´¦ÓÚ¾²Ö¹×´Ì¬£¬ÏÖÓÃˮƽºãÁ¦F½«Ä¾°åˮƽÏòÓÒ¼ÓËÙ³é³ö£¬Ð¡½ðÊô¿éA»¬µ½Ë®Æ½µØÃæÉϺó£¬ÓÖÔÚµØÃæÉÏ»¬ÐÐÁËs=0.4mºóÍ£ÏÂÀ´£®Ç󣺣¨gÈ¡10m/s2£©
£¨1£©½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ˲¼äµÄËٶȴóС£»
£¨2£©½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ֮ǰ£¬Ä¾°åBµÄ¼ÓËٶȴóС£»
£¨3£©¼ÓÔÚľ°åBÉϵÄˮƽºãÁ¦FµÄ´óС£®
·ÖÎö£º£¨1£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³ö½ðÊô¿é´Óľ°å»¬ÏÂÔÚµØÃæÉϵļÓËٶȣ¬½áºÏËÙ¶ÈλÒƹ«Ê½Çó³ö½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ˲¼äµÄËٶȴóС£®
£¨2£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³öA×öÔȼÓËÙÖ±ÏßÔ˶¯µÄ¼ÓËٶȣ¬´Ó¶øµÃ³öAÔ˶¯µÄʱ¼ä£¬½áºÏÔ˶¯Ñ§¹«Ê½¹«Ê½£¬×¥×¡A¡¢BµÄλÒƹØϵÇó³öľ°åBµÄ¼ÓËٶȣ®
£¨3£©¶ÔB¸ôÀë·ÖÎö£¬Í¨¹ýÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³ö¼ÓÔÚľ°åBÉϵÄˮƽºãÁ¦FµÄ´óС£®
½â´ð£º½â£º£¨1£©Ð¡½ðÊô¿éA´Óľ°åBÉÏ»¬ÏºóÔÚµØÃæÉÏ×öÔȼõËÙÖ±ÏßÔ˶¯£¬Æä¼ÓËÙ¶Èa=¦Ì2g=5m/s2£¬
¹ÊС½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ˲¼äµÄËÙ¶Èv=
2as
=2m/s
£®
£¨2£©Ð¡½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ֮ǰÔÚľ°åÉÏ×öÔȼÓËÙÖ±ÏßÔ˶¯£¬Æä¼ÓËÙ¶Èa1=¦Ì1g=1m/s2£®
Æä¼ÓËÙ¶Èa1=
v
a1
=2s
£®
λÒÆs1=
vt
2
=2m
£®
Éèľ°åµÄ¼ÓËÙ¶ÈΪa2£¬ÔòÔÚÕâ¶Îʱ¼äÄÚľ°åµÄλÒÆs2=
1
2
a2t2
£¬ÓÖs2-s1=L£®
ÁªÁ¢½âµÃa2=2m/s2£®
£¨3£©¶Ôľ°åÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉÓÐF-¦Ì1m1g-¦Ì2£¨m1+m2£©g=m2a2£®
½âµÃF=20N£®
´ð£º£¨1£©½ðÊô¿éA´Óľ°åBÉÏ»¬ÏÂ˲¼äµÄËٶȴóСΪ2m/s£®
£¨2£©Ä¾°åBµÄ¼ÓËٶȴóСΪ2m/s2£®
£¨3£©¼ÓÔÚľ°åBÉϵÄˮƽºãÁ¦FµÄ´óСΪ20N£®
µãÆÀ£º½â¾ö±¾ÌâµÄ¹Ø¼üÀíÇåA¡¢BµÄÔ˶¯¹ý³Ì£¬½áºÏÅ£¶ÙµÚ¶þ¶¨ÂÉ¡¢Ô˶¯Ñ§¹«Ê½Áé»îÇó½â£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©Æøµæµ¼¹ìÊdz£ÓõÄÒ»ÖÖʵÑéÒÇÆ÷£¬ËüÊÇÀûÓÃÆø±Ãʹ´ø¿×µÄµ¼¹ìÓ뻬¿éÖ®¼äÐγÉÆøµæ£¬Ê¹»¬¿éÐü¸¡ÔÚµ¼¹ìÉÏ£¬»¬¿éÔÚµ¼¹ìÉϵÄÔ˶¯¿ÉÊÓΪûÓÐĦ²Á£®ÎÒÃÇ¿ÉÒÔÓôøÊúÖ±µ²°åCºÍDµÄÆøµæµ¼¹ìºÍ»¬¿éAºÍBÑéÖ¤¶¯Á¿Êغ㶨ÂÉ£¬ÊµÑé×°ÖÃÈçͼËùʾ£¬²ÉÈ¡µÄʵÑé²½ÖèÈçÏ£º
a£®ÓÃÌìƽ·Ö±ð²â³ö»¬¿éA¡¢BµÄÖÊÁ¿mA¡¢mB£»
b£®µ÷ÕûÆøµæµ¼¹ì£¬Ê¹µ¼¹ì´¦ÓÚˮƽ£º
c£®ÔÚAºÍB¼ä·ÅÈëÒ»¸ö±»Ñ¹ËõµÄÇáÖÊÇÒ¼«¶ÌµÄµ¯»É£¬Óõ綯¿¨ÏúËø¶¨£¬¾²Ö¹·ÅÖÃÔÚÆøµæµ¼¹ìÉÏ£»
d£®Óÿ̶ȳ߲â³öAµÄ×ó¶ËÖÁC°åµÄ¾àÀëL1£»
e£®°´ÏµçÅ¥·Å¿ª¿¨Ïú£¬Í¬Ê±ÓüÆʱÆ÷¼Ç¼»¬¿éA¡¢B´Ó¿ªÊ¼µ½·Ö±ðÅöײC¡¢Dµ²°åʱËùÓÃʱ¼ät1¡¢t2£»
¢ÙʵÑéÖл¹Ó¦²âÁ¿µÄÎïÀíÁ¿ÊÇ
BµÄÓÒ¶ËÖÁD°åµÄ¾àÀëL2
BµÄÓÒ¶ËÖÁD°åµÄ¾àÀëL2
£®
¢ÚÀûÓÃÉÏÊö²âÁ¿µÄʵÑéÊý¾Ý£¬ÑéÖ¤¶¯Á¿Êغ㶨Âɵıí´ïʽÊÇ
mA
L1
t1
-mB
L2
t2
=0
mA
L1
t1
-mB
L2
t2
=0
£®
£¨2£©ÔÚ¡°ÑéÖ¤»úеÄÜÊغ㶨ÂÉ¡±µÄʵÑéÖУ¬ÀûÓÃÖØ´¸ÍÏ×ÅÖ½´ø×ÔÓÉÏÂÂäͨ¹ý´òµã¼ÆʱÆ÷²¢´ò³öһϵÁеĵ㣬¶ÔÖ½´øÉϵĵ㼣½øÐвâÁ¿£¬¼´¿ÉÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®
¢ÙÔÚʵÑé¹ý³ÌÖУ¬ÏÂÁеÄ˵·¨ÕýÈ·µÄÊÇ£º
BD
BD
£®
A£®±ØÐëʹÓõIJâÁ¿ÒÇÆ÷ÓУº´òµã¼ÆʱÆ÷¡¢Ø²Æ½ºÍ¿Ì¶È³ß
B£®Ö½´øÓë´òµã¼ÆʱÆ÷µÄÁ½¸öÏÞλ¿×ÒªÔÚͬһÊúÖ±ÏßÉÏ
C£®ÊµÑéÖÐÈôÆäËûÌõ¼þ²»±äÇÒ¿ÕÆø×èÁ¦ºã¶¨Ê±£¬Ñ¡ÓÃÖØ´¸ÖÊÁ¿µÄ´óС²»Ó°ÏìʵÑéµÄÎó²î
D£®Ñ¡ÓÃÖ½´øÉÏÈÎÒâ¿É¼ÆËãËٶȵÄÁ½µã¶¼¿ÉÒÔÓÃÀ´ÑéÖ¤»úеÄÜÊغ㶨ÂÉ
¢Ú°²×°ºÃʵÑé×°Öã¬ÕýÈ·½øÐÐʵÑé²Ù×÷£¬´Ó´ò³öµÄÖ½´øÖÐÑ¡³ö·ûºÏÒªÇóµÄÖ½´ø£¬ÈçͼËùʾ£®Í¼ÖÐOµãΪΪ´òµãÆðʼµã£¬ÇÒËÙ¶ÈΪÁ㣮

Ñ¡È¡Ö½´øÉÏ´ò³öµÄÁ¬ÐøµãA¡¢B¡¢C£¬¡­£¬²â³öÆäÖÐE¡¢F¡¢Gµã¾à´òµãÆðʼµãOµÄ¾àÀë·Ö±ðΪh1¡¢h2¡¢h3£¬ÒÑÖªÖØ´¸ÖÊÁ¿Îªm£¬µ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£¬´òµã¼ÆʱÆ÷´òµãÖÜÆÚΪT£®ÎªÑéÖ¤´ËʵÑé¹ý³ÌÖлúеÄÜÊÇ·ñÊغ㣬ÐèÒª¼ÆËã³ö´Ó´òÏÂOµãµ½´òÏÂFµãµÄ¹ý³ÌÖУ¬ÖØ´¸ÖØÁ¦ÊÆÄܵļõÉÙÁ¿¡÷EP=
mgh2
mgh2
£¬¶¯ÄܵÄÔö¼ÓÁ¿¡÷EK
=
m(h3-h1)2
8T2
=
m(h3-h1)2
8T2
£¨ÓÃÌâÖÐËù¸ø×Öĸ±íʾ£©£®
¢ÛÒÔ¸÷µãµ½ÆðʼµãµÄ¾àÀëhΪºá×ø±ê£¬ÒÔ¸÷µãËٶȵÄƽ·½v2Ϊ×Ý×ø±ê½¨Á¢Ö±½Ç×ø±êϵ£¬ÓÃʵÑé²âµÃµÄÊý¾Ý»æ³öv2-hͼÏߣ¬ÈçͼËùʾ£®´Óv2-hͼÏßÇóµÃÖØ´¸ÏÂÂäµÄ¼ÓËÙ¶Èg'=
9.67
9.67
m/s2£®£¨±£Áô3λÓÐЧÊý×Ö£©
ÈçͼËùʾ£¬×ã¹»³¤µÄ¹â»¬¾øԵˮƽ̨×ó¶Ë¹Ì¶¨Ò»±»Ñ¹ËõµÄ¾øÔµÇáÖʵ¯»É£¬Ò»¸öÖÊÁ¿m=0.04kg¡¢µçÁ¿q=+2¡Á10-4cµÄ¿ÉÊÓΪÖʵãµÄ´øµçСÇòÓ뵯»É½Ó´¥µ«²»Ë¨½Ó£®Ä³Ò»Ë²¼äÊͷŵ¯»Éµ¯³öСÇò£¬Ð¡Çò´Óˮƽ̨ÓÒ¶ËAµã·É³ö£¬Ç¡ºÃÄÜûÓÐÅöײµØÂäµ½´Ö²ÚÇãб¹ìµÀµÄ×î¸ßBµã£¬²¢ÑعìµÀ»¬Ï£®ÒÑÖªABµÄÊúÖ±¸ß¶Èh=0.45m£¬Çãб¹ìµÀÓëˮƽ·½Ïò¼Ð½ÇΪ¦Á=37¡ã¡¢Çãб¹ìµÀ³¤ÎªL=2.0m£¬´øµçСÇòÓëÇãб¹ìµÀµÄ¶¯Ä¦²ÁÒòÊý¦Ì=0.5£®Çãб¹ìµÀͨ¹ý¹â»¬Ë®Æ½¹ìµÀCDÓë¹â»¬ÊúÖ±Ô²¹ìµÀÏàÁ¬£¬ÔÚCµãûÓÐÄÜÁ¿Ëðʧ£¬ËùÓйìµÀ¶¼¾øÔµ£¬Ô˶¯¹ý³ÌСÇòµÄµçÁ¿±£³Ö²»±ä£®Ö»Óйýɽ³µÄ£Ð͵ÄÊúÖ±Ô²¹ìµÀ´¦ÔÚ·¶Î§×ã¹»´óÊúÖ±ÏòϵÄÔÈÇ¿µç³¡ÖУ¬³¡Ç¿E=2.0¡Á103V/m£®£¨cos37¡ã=0.8£¬sin37¡ã=0.6£¬È¡g=10m/s2£©Çó£º
£¨1£©±»ÊÍ·ÅÇ°µ¯»ÉµÄµ¯ÐÔÊÆÄÜ£¿
£¨2£©ÒªÊ¹Ð¡Çò²»À뿪¹ìµÀ£¨Ë®Æ½¹ìµÀ×ã¹»³¤£©£¬ÊúÖ±Ô²»¡¹ìµÀµÄ°ë¾¶Ó¦¸ÃÂú×ãʲôÌõ¼þ£¿
£¨3£©Èç¹ûÊúÖ±Ô²»¡¹ìµÀµÄ°ë¾¶R=0.9m£¬Ð¡Çò½øÈë¹ìµÀºó¿ÉÒÔÓжàÉÙ´Îͨ¹ýÊúÖ±Ô²¹ìµÀÉϾàˮƽ¹ìµÀ¸ßΪ0.01mµÄijһµãP£¿
¾«Ó¢¼Ò½ÌÍø

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø