题目内容
如图是甲、乙两物体相对同一原点的s-t图像,则下列说法正确的是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241507469752494.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241507469752494.jpg)
A.甲、乙都做变速直线运动 |
B.甲、乙运动的出发点相距![]() |
C.乙比甲的运动要快些 |
D.甲比乙晚出发![]() |
BD
试题分析:由图像知甲、乙都做匀速直线运动,A错;甲运动的出发点在参考点,乙运动的出发点相距参考点为
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150747007283.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150747007283.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150747147292.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824150747147292.png)
点评:本题学生清楚s-t图线的斜率表示物体速度的大小,交点表示两物体相遇。
![](http://thumb2018.1010pic.com/images/loading.gif)
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