ÌâÄ¿ÄÚÈÝ
(1£©ÈÈÃôµç×èÊÇ´«¸Ðµç·Öг£Óõĵç×ÓÔª¼þ¡£ÏÖÓ÷ü°²·¨Ñо¿ÈÈÃôµç×èÔÚ²»Í¬Î¶Èϵķü°²ÌØÐÔÇúÏߣ¬ÒªÇóÌØÐÔÇúÏß¾¡¿ÉÄÜÍêÕû¡£ÒÑÖª³£ÎÂÏ´ý²âÈÈÃôµç×èµÄ×èÖµÔ¼4~5¦¸¡£ÈÈÃôµç×èºÍζȼƲåÈë´øÈûµÄ±£Î±ÖУ¬±ÄÚÓÐÒ»¶¨Á¿µÄÀäË®£¬ÆäËü±¸ÓõÄÒDZíºÍÆ÷¾ßÓУºÊ¢ÓÐÈÈË®µÄÈÈË®±£¨Í¼ÖÐδ»³ö£©¡¢µçÔ´£¨3V¡¢ÄÚ×è¿ÉºöÂÔ£©¡¢Ö±Á÷µçÁ÷±í£¨ÄÚ×èÔ¼1¦¸£©¡¢Ö±Á÷µçѹ±í£¨ÄÚ×èÔ¼5k¦¸£©¡¢»¬¶¯±ä×èÆ÷£¨0~20¦¸£©¡¢¿ª¹Ø¡¢µ¼ÏßÈô¸É¡£
![]()
![]()
![]()
¢ÙÔÚͼ12£¨a£©µÄ·½¿òÖл³öʵÑéµç·ͼ£¬ÒªÇó²âÁ¿Îó²î¾¡¿ÉÄÜС¡£(4·Ö)
¢Ú¸ù¾Ýµç·ͼ£¬ÔÚͼ12£¨b£©µÄʵÎïͼÉÏÁ¬Ïß¡£(4·Ö)
¢Û¼òҪд³öÍê³É½ÓÏߺóµÄÖ÷ҪʵÑé²½Öè
1)¡¢Íù±£Î±ÖмÓÈëÈÈË®£¬ÉԵȶÁ³öζÈÖµ¡£
2)¡¢ .(2·Ö)
3)¡¢Öظ´¢Ù£¬¢Ú²â³ö²»Í¬Î¶ÈϵÄÊý¾Ý¡£
4)¡¢ .(2·Ö)
£¨2£©¹ã·ºÓ¦ÓÃÓÚÊÒÄÚ¿Õµ÷¡¢µç±ùÏäºÍ΢²¨Â¯µÈ¼ÒÓõçÆ÷ÖеÄζȴ«¸ÐÆ÷£¬ÊÇÀûÓÃÈÈÃôµç×èËæÎ¶ȱ仯¶ø±ä»¯µÄÌØÐÔ¹¤×÷µÄ¡£ÔÚͼ¼×ÖУ¬
µçÔ´µÄµç¶¯ÊÆE = 9.0 V£¬ÄÚµç×è²»¿ÉºöÂÔ£»CΪ
ÄÚ×è²»¼ÆµÄÁéÃôµçÁ÷±í£»R0Ϊ±£»¤µç×裻RΪÈÈ
Ãôµç×裬Æäµç×èÖµÓëζȱ仯¹ØÏµÈçͼÒÒµÄR- t
ͼÏóËùʾ¡£ÔòÈÈÃôµç×èRÓëÉãÊÏζÈtµÄ¹ØÏµÎª
R= £»±ÕºÏµç¼üS£¬µ±RµÄζȵÈÓÚ
40¡æÊ±£¬µçÁ÷±íʾÊýI1=2.25 mA£¬Ôòµ±µçÁ÷±íµÄ
ʾÊýI2=3.6 mAʱ£¬ÈÈÃôµç×èRµÄζÈÊÇ________ÉãÊ϶ȡ£(ÿ¿Õ1·Ö)
![]()
![]()
£¨1£©¢ÙÈçͼËùʾ £¨3·Ö£©
![]()
¢ÚÁ¬Ïߣ¨4·ÖÂÔ¡£2¸öÁ¿³ÌÑ¡¶ÔµÃ2·Ö£©
¢Û£¨4·Ö£©¢Ù¡¢Íù±£Î±ÖмÓÈëÈÈË®£¬ÉԵȶÁ³öζÈÖµ¡£
¢Ú¡¢µ÷½ÚR£¬¿ìËÙ²â³ö¶à×éI£¬UÖµ¡£
¢Û¡¢Öظ´¢Ù£¬¢Ú²â³ö²»Í¬Î¶ÈϵÄÊý¾Ý¡£
¢Ü¡¢»æ³ö¸÷ζÈÏÂÈÈÃôµç×èµÄ·ü°²ÌØÐÔÇúÏß¡£
(2)R = ¨C1.875¡Á10 -2 t + 4.25 £¨2·Ö£©£¬ 120 £¨2·Ö£©