ÌâÄ¿ÄÚÈÝ

£¨2009?»ÆÆÖÇø¶þÄ££©ÓÒͼΪARJ21-700·É»úÔÚÉϺ£³É¹¦ÊµÏÖÊ׷ɵÄÐÛ×Ë£¬ËüÊÇÖйúÊ×¼Ü×ÔÖ÷ÑÐÖÆ¡¢ÓµÓÐÍêÈ«×ÔÖ÷֪ʶ²úȨµÄÐÂÐÍÎÐÉÈÖ§Ïß·É»ú£®¼Ù¶¨·É»úµÄÖÊÁ¿Îªm£¬ÒÔˮƽËÙ¶Èv0·ÉÀëÅܵÀºóÖð½¥ÉÏÉý£¬Ôڴ˹ý³ÌÖÐˮƽËٶȱ£³Ö²»±ä£¬Í¬Ê±Êܵ½ÖØÁ¦ºÍÊúÖ±ÏòÉϵĺ㶨ÉýÁ¦£¨¸ÃÉýÁ¦ÓÉÆäËüÁ¦µÄºÏÁ¦Ìṩ£¬²»º¬ÖØÁ¦£©£®ÏÖ²âµÃµ±·É»ú´Ó·ÉÀëµØÃ濪ʼËãÆð£¬ÔÚˮƽ·½ÏòµÄλÒÆΪsʱ£¬ËüµÄÉÏÉý¸ß¶ÈΪh£®Çó£º
£¨1£©·É»úÊܵ½µÄÉýÁ¦´óС£»
£¨2£©´Ó·ÉÀëµØÃ濪ʼËãÆ𣬷ɻúÉÏÉýÖÁh¸ß¶ÈµÄ¹ý³ÌÖÐÉýÁ¦Ëù×÷µÄ¹¦¼°Ôڸ߶Èh´¦·É»úµÄ¶¯ÄÜ£®
·ÖÎö£º£¨1£©·É»ú×öÀàƽÅ×Ô˶¯£¬¸ù¾ÝÔ˶¯Ñ§¹«Ê½ÓëÅ£¶ÙµÚ¶þ¶¨ÂÉÏà½áºÏ£¬´Ó¶ø¼´¿ÉÇó½â£»
£¨2£©¸ù¾Ý¹¦µÄ±í´ïʽÓ붯Äܱí´ïʽ£¬¼´¿ÉÇó½â£®
½â´ð£º½â£º£¨1£©·É»úˮƽËٶȲ»±ä£¬ÔòÓУºs=v0t                                
y·½Ïò¼ÓËٶȺ㶨£¬ÔòÓÐ h=
1
2
at2
                                           
ÏûÈ¥t¼´µÃ  a=
2h
s2
v
2
0
                                              
ÓÉÅ£¶ÙµÚ¶þ¶¨ÂÉ  F=mg+ma
F=mg(1+
2h
v
2
0
gs2
)
                      
£¨2£©ÉýÁ¦×ö¹¦W=Fh=mgh(1+
2h
v
2
0
gs2
)
                             
ÔÚh´¦vt=at=
2ah
=
2hv0
s
                                      
¡àEk=
1
2
m(
v
2
0
+
v
2
t
)
=
1
2
m
v
2
0
(1+
4h2
s2
)
     
´ð£º£¨1£©·É»úÊܵ½µÄÉýÁ¦´óСΪF=mg(1+
2h
v
2
0
gs2
)
£»
£¨2£©´Ó·ÉÀëµØÃ濪ʼËãÆ𣬷ɻúÉÏÉýÖÁh¸ß¶ÈµÄ¹ý³ÌÖÐÉýÁ¦Ëù×÷µÄ¹¦mgh(1+
2h
v
2
0
gs2
)
¼°Ôڸ߶Èh´¦·É»úµÄ¶¯ÄÜ
1
2
m
v
2
0
(1+
4h2
s2
)
£®
µãÆÀ£º¿¼²éÎïÌå×öÀàƽÅ×Ô˶¯ÖУ¬Ô˶¯Ñ§¹«Ê½ÓëÅ£¶ÙµÚ¶þ¶¨ÂÉÏà×ÛºÏÔËÓ㬲¢ÕÆÎÕ¹¦Ó붯Äܱí´ïʽ£¬Í¬Ê±Ñ§»áÔ˶¯µÄ·Ö½âÓëºÏ³ÉµÄÓ¦Óã®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø