ÌâÄ¿ÄÚÈÝ

Òª²â¶¨Ò»¸ö°×¸ÐϵÊýºÜ´óµÄÏßȦLµÄÖ±Á÷µç×裬ʵÑéÊÒÌṩÏÂÁÐÆ÷²Ä£º
¢Ù´ý²âÏßȦL£¬×èֵԼΪ2¦¸£¬¶î¶¨µçÁ÷Ϊ2A£¨·ûºÅ£©
¢ÚµçÁ÷±íA1£¬Á¿³ÌΪ0.6A£¬ÄÚ×èΪ0.2¦¸£¨·ûºÅ£©
¢ÛµçÁ÷±íA2Á¿³ÌΪ3A£¬ÄÚ×èԼΪ0.2¦¸£¨·ûºÅ£©
¢Ü±ä×èÆ÷R1£¬×èֵΪ0-10¦¸£¬±ä×èÆ÷R2×èֵΪ0-lk¦¸£¨·ûºÅ£©
¢Ýµç³ØE£¬µç¶¯ÊÆΪ9V£¬ÄÚ×èºÜС£¨·ûºÅ£©
¢Þ¶¨Öµµç×èR3=10¦¸£¬Ry=100¦¸£¨·ûºÅ£©
¢ß¿ª¹ØS1£¬S2£¨·ûºÅ£©
ÒªÇóʵÑéʱ£¬¸Ä±ä±ä×èÆ÷µÄ×èÖµ£¬¿ÉʹÔÚ¾¡¿ÉÄÜ´óµÄ·¶Î§ÄÚ²âµÃ¶à×éA1±í£¬A2±íµÄ¶ÁÊý
I1¡¢I2£¬È»ºóÀûÓÃI1-I2µÄͼÏó£¬Çó³öµç¸ÐÏßȦµÄµç×裮
£¨1£©ÊµÑéÖж¨Öµµç×èӦѡÓÃ______£¬±ä×èÆ÷ӦѡÓÃ______
£¨2£©ÇëÔÚ·½¿òÄÚ»­³öµç·ͼ£®
£¨3£©ÊµÑé½áÊøʱӦÏȶϿª¿ª¹Ø______
£¨4£©ÊµÑé²âµÃÊý¾ÝÈçͼI1-I2Ëùʾ£¬Ôòµç¸ÐÏßȦµÄÖ±Á÷µç×èֵΪ______£®£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨1£©²ÉÓÃÒÑÖªÄÚ×èµÄСÁ¿³ÌµçÁ÷±íA1Ìæ´úµçѹ±í²âÁ¿µçѹ£¬ÐèÒª´®ÁªÒ»¸ö´óÓÚµÈÓÚR=
2¡Á2
0.6
¦¸=6.7¦¸
µÄ¶¨Öµµç×裮ËùÒÔʵÑéÖж¨Öµµç×èӦѡÓÃ×èֵΪ10¦¸µÄR3£¬»¬¶¯±ä×èÆ÷ӦѡÓÃ×èֵΪ1¡«10¦¸µÄR1£®
£¨2£©²âÁ¿ÏßȦµÄµç×èÒ»°ã²ÉÓ÷ü°²·¨£¬ÎªÁË·ÀÖ¹²âÁ¿×Ô¸ÐϵÊýºÜ´óµÄÏßȦ¶Ïµç²úÉúµÄ´ó×ԸеçÁ÷ÉÕ»µµç±í£¬¿ÉÓëµç±í´®ÁªÒ»¸ö¿ª¹Ø£® ÓÉÓÚ´ý²âÏßȦLµÄ×èֵԼΪ2¦¸£¬¶î¶¨µçÁ÷Ϊ2A£¬×î´óµçѹΪ4V£¬¶øµçÔ´µç¶¯ÊÆΪ9V£¬ËùÒÔ±ØÐë²ÉÓ÷Öѹµç·£¬µçÁ÷±íÍâ½Óµç·½øÐвâÁ¿£¬µç·ÈçͼËùʾ£®
£¨3£©ÊµÑé½áÊøʱӦÏȶϿª¿ª¹ØS2
£¨4£©ÓÉ
I2
I1
=
RL+R3+r
RL
=6

µÃ£ºRL=
R3+r
5
=2.04¦¸£®ÓÉÓÚ±£ÁôÁ½Î»ÓÐЧÊý×Ö£¬ËùÒÔΪ2.0¦¸£®
¹Ê´ð°¸Îª£º£¨1£©R3£¬R1
£¨2£©ÈçÓÒͼ
£¨3£©S2
£¨4£©2.0¦¸
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø