ÌâÄ¿ÄÚÈÝ

ijͬѧÀûÓôòµã¼ÆʱÆ÷¡¢ÒÑÖªÖÊÁ¿ÎªmµÄ»¬¿é¡¢¿Éµ÷½Ú¸ß¶ÈµÄбÃæ¡¢Ö±³ßµÈÒÇÆ÷½øÐС¶Ì½¾¿¶¯Äܶ¨Àí¡·µÄʵÑ飨Èçͼ1£©£¬ËûÊ×ÏȽ«´òµã¼ÆʱÆ÷¹Ì¶¨ÔÚбÃæµÄÉ϶ˣ¬²¢½«»¬¿éÓëÖ½´øÏàÁ¬£¬ÈÃÖ½´ø´©¹ý´òµã¼ÆʱÆ÷£¬½ÓͨµÍѹ½»Á÷µçÔ´£¨ÒÑ֪ƵÂÊΪf£©ºóÊÍ·Å»¬¿é£¬´òµã¼ÆʱÆ÷ÔÚÖ½´øÉÏ´òÏÂһϵÁмÇÊýµã£®
»Ø´ðÏÂÁÐÎÊÌ⣺£¨ÓÃÒÑÖª×Öĸ±íʾ£©
¾«Ó¢¼Ò½ÌÍø
£¨1£©Ð´³öÓ°Ï컬¿é¶¯Äܱ仯µÄÖ÷ÒªÒòËØ
£¨2£©¸ÃʵÑé̽¾¿ÖÐΪÁËÇóºÏÍâÁ¦£¬Ó¦ÏÈÇó³ö»¬¿éÓëбÃæµÄ¶¯Ä¦²ÁÒòÊý£®¸Ãͬѧͨ¹ý¶à´Îµ÷½ÚбÃæµÄ¸ß¶È£¬µÃµ½Ò»Ìõ´òµã¼ä¾à¾ùÔȵÄÖ½´ø£¨Èçͼ2£©£¬´ËʱÏà¶ÔÓ¦µÄбÃ泤ΪLбÃæ¸ßΪh£®ÓÉ´Ë¿ÉÇó³ö»¬¿éÓëбÃæµÄ¶¯Ä¦²ÁÒòÊýΪ¦Ì=
 

£¨3£©±£³ÖбÃ泤¶È²»±ä£¬Éý¸ßбÃæ¸ß¶Èµ½H£¨H£¾h£©£¬¸ÃͬѧÔÚʵÑéÖеõ½Ò»Ìõ´òµãÇåÎúµÄÖ½´ø£¨Èçͼ3£©£¬ÓÃÖ±³ß²â³öS1 S2 S3£¬¶ÔA¡¢BÁ½µãÑо¿£º
´Ëʱ»¬¿éÔÚA¡¢BÁ½µãµÄËٶȴóСΪ£ºVA=
 
£¬VB=
 

£¨4£©Èç¹û¸ÃͬѧÔڼǼÊý¾Ýʱ¸÷ÎïÀíÁ¿µÄµ¥Î»·Ö±ðÊÇ£ºL¡¢H¡¢S1¡¢S2¡¢S3Ϊcm£¬mΪkg£¬fΪHz£¬gΪm/s2£¬¶ÔAB¶Î½øÐÐÑо¿£¬ÔÚʵÑéÔÊÐíµÄÎó²î·¶Î§ÄÚ£¬¸Ãͬѧ¸ù¾Ý¼Ç¼µÄÊý¾ÝÖ±½Ó¼ÆËãºÏÍâÁ¦¶Ô»¬¿éËù×öµÄ¹¦ÎªW£¬»¬¿é¶¯ÄܵĸıäÁ¿Îª¡÷Ek£¬½á¹û·¢ÏÖÁ½ÕߵIJî±ðºÜ´ó£¬Çë·ÖÎöÆäÔ­Òò£®Ð´³ö¸Ãͬѧ¼ÆËã³öµÄÊýÖµWÓë¡÷EkÖ®¼äÕýÈ·¹ØϵµÄ±í´ïʽ£®
 
£®
·ÖÎö£º£¨1£©¶Ô»¬¿é½øÐÐÊÜÁ¦·ÖÎö¿ÉÖª£¬»¬¿éÏ»¬µÄ¹ý³ÌÖÐÊܵ½ÖØÁ¦£®Ð±ÃæµÄÖ§³ÖÁ¦ºÍĦ²ÁÁ¦µÄ×÷Óã¬ÆäÖÐÖ§³ÖÁ¦²»×ö¹¦£¬Òò´Ë£¬Ó°Ï컬¿é¶¯Äܱ仯µÄÖ÷ÒªÒòËØÊÇÖØÁ¦ºÍĦ²ÁÁ¦£®
£¨2£©´Óͼ2ÖпÉÖª£¬»¬¿é×öÔÈËÙÖ±ÏßÔ˶¯£¬Êܵ½µÄºÏÍâÁ¦µÈÓÚ0£»
£¨3£©AµãµÄ˲ʱËٶȵÈÓÚOB¶ÎµÄƽ¾ùËٶȣ¬BµãµÄ˲ʱËٶȵÈÓÚAC¶ÎµÄƽ¾ùËٶȣ»
£¨4£©¸ÃͬѧʹÓõij¤¶ÈµÄµ¥Î»²»Í³Ò»£®¿ÉÄÜÊÇ´íÎóµÄÖ÷ÒâÔ­Òò£®
½â´ð£º½â£º£¨1£©¶Ô»¬¿é½øÐÐÊÜÁ¦·ÖÎö¿ÉÖª£¬»¬¿éÏ»¬µÄ¹ý³ÌÖÐÊܵ½ÖØÁ¦£®Ð±ÃæµÄÖ§³ÖÁ¦ºÍĦ²ÁÁ¦µÄ×÷Óã¬ÆäÖÐÖ§³ÖÁ¦²»×ö¹¦£¬Òò´Ë£¬Ó°Ï컬¿é¶¯Äܱ仯µÄÖ÷ÒªÒòËØÊÇÖØÁ¦ºÍĦ²ÁÁ¦£®
£¨2£©´Óͼ2ÖпÉÖª£¬»¬¿éËù×öµÄÔ˶¯ÎªÔÈËÙÖ±ÏßÔ˶¯£¬Êܵ½µÄºÏÍâÁ¦µÈÓÚ0£»ËùÒÔ£ºmgsin¦È=¦Ìmgcos¦È
ÕûÀíµÃ£º¦Ì=tan¦È=
h
L2-h2

£¨3£©AµãµÄ˲ʱËٶȵÈÓÚOB¶ÎµÄƽ¾ùËٶȣ¬vA=
OB
2T
=
s2?f
2
BµãµÄ˲ʱËٶȵÈÓÚAC¶ÎµÄƽ¾ùËÙ¶ÈvB=
AC
2T
=
(s3-s1)?f
2
£»
£¨4£©¸ÃͬѧʹÓõij¤¶ÈµÄµ¥Î»²»Í³Ò»£¬µ¼ÖÂ̽¾¿µÄ½áÂÛ²»¶Ô£®¿ÉÄÜÊÇ´íÎóµÄÖ÷ÒâÔ­Òò£®  ӦΪW=¡÷Ek¡Á 10 -2£®
¹Ê´ð°¸Îª£º£¨1£©Ó°Ï컬¿é¶¯Äܱ仯µÄÖ÷ÒªÒòËØÊÇÖØÁ¦ºÍĦ²ÁÁ¦£®£¨2£©¦Ì=
h
L2-h2
£»
 £¨3£©
s2?f
2
£»  
(s3-s1)?f
2
£»   £¨4£© W=¡÷Ek¡Á 10 -2
µãÆÀ£ºÔÚƽʱµÄ×öÌâ»òʵÑéÊý¾ÝµÄ´¦ÀíÖУ¬Ê×ÏÈҪͳһ¼ÆËãʹÓõĵ¥Î»£¬Èç¸ÃͬѧʹÓõij¤¶ÈµÄµ¥Î»²»Í³Ò»£¬µ¼ÖÂ̽¾¿µÄ½áÂÛ²»¶Ô£®Çмǣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©ÔÚÓá°Í¼Ï󷨡±´¦ÀíʵÑéÊý¾Ýʱ£¬ÎªÁ˼õÉÙÎó²î
BD
BD
£»
A£®Ó¦Ê¹×Ý¡¢ºá×ø±êÿµ¥Î»³¤¶È±íʾµÄÊýÖµ´óһЩ
B£®Ó¦Ê¹×Ý¡¢ºá×ø±êÿµ¥Î»³¤¶È±íʾµÄÊýֵСһЩ
C£®ÎªÊ¹Í¼Ïßͨ¹ýÿ¸öʵÑéÊý¾Ýµã£¬Ó¦Ê¹Í¼Ïß»­³ÉÕÛÏß
D£®Ó¦Ê¹Í¼Ïß»­³ÉÖ±Ïß»ò¹â»¬ÇúÏߣ¬ÈÃʵÑéÊý¾Ýµã´óÖ¾ùÔÈ·Ö²¼ÔÚͼÏ߸½½ü£¬¶ÔÓÚ¸ö±ðÀëÏß½ÏÔ¶µÄµã¿ÉÒÔÉáÈ¥
£¨2£©Ä³Í¬Ñ§Òª½øÐÐ̽¾¿ÔȱäËÙÖ±ÏßÔ˶¯ÊµÑ飬ÇëÔÚÏÂÃæÁгöµÄʵÑéÆ÷²ÄÖУ¬Ñ¡³ö±¾ÊµÑéÖв»ÐèÒªµÄÆ÷²ÄÌîÔÚºáÏßÉÏ£¨Ìî±àºÅ£©£º
¢Ú¢Ü¢ß
¢Ú¢Ü¢ß
£®
¢Ù´òµã¼ÆʱÆ÷   ¢ÚÌìƽ   ¢ÛµÍѹ½»Á÷µçÔ´  ¢ÜµÍѹֱÁ÷µçÔ´   ¢ÝϸÉþºÍÖ½´ø   ¢Þ¹³ÂëºÍС³µ   ¢ßÃë±í   ¢àÒ»¶ËÓл¬Âֵij¤Ä¾°å   ¢á¿Ì¶È³ß
£¨3£©Ä³Í¬Ñ§ÀûÓôòµã¼ÆʱÆ÷Ëù¼Ç¼µÄÖ½´øÀ´Ñо¿×öÔȱäËÙÖ±ÏßÔ˶¯Ð¡³µµÄÔ˶¯Çé¿ö£¬ÊµÑéÖлñµÃÒ»ÌõÖ½´ø£¬ÈçͼËùʾ£¬ÆäÖÐÁ½ÏàÁÚ¼ÆÊýµã¼äÓÐËĸöµãδ»­³ö£®ÒÑÖªËùÓõçÔ´µÄƵÂÊΪ50HZ£¬Ôò´òAµãʱС³µÔ˶¯µÄËÙ¶ÈvA=
0.337
0.337
m/s£¬Ð¡³µÔ˶¯µÄ¼ÓËÙ¶Èa=
0.393
0.393
m/s2£®£¨½á¹ûÒªÇó±£ÁôÈýλÓÐЧÊý×Ö£©
£¨2009?ÕØÇìһģ£©Ä³Í¬Ñ§ÀûÓôòµã¼ÆʱÆ÷ºÍÆøµæµ¼¹ì×öÑéÖ¤¶¯Á¿Êغ㶨ÂɵÄʵÑ飮Æøµæµ¼¹ì×°ÖÃÈçͼaËùʾ£¬ËùÓõÄÆøµæµ¼¹ì×°ÖÃÓɵ¼¹ì¡¢»¬¿é¡¢µ¯Éä¼ÜµÈ×é³É£®ÔÚ¿ÕÇ»µ¼¹ìµÄÁ½¸ö¹¤×÷ÃæÉϾùÔÈ·Ö²¼×ÅÒ»¶¨ÊýÁ¿µÄС¿×£¬Ïòµ¼¹ì¿ÕÇ»ÄÚ²»¶ÏͨÈëѹËõ¿ÕÆø£¬¿ÕÆø»á´ÓС¿×ÖÐÅç³ö£¬Ê¹»¬¿éÎȶ¨µØƯ¸¡ÔÚµ¼¹ìÉÏ£¬ÕâÑù¾Í´ó´ó¼õСÁËÒò»¬¿éºÍµ¼¹ìÖ®¼äµÄĦ²Á¶øÒýÆðµÄÎó²î£®
£¨1£©ÏÂÃæÊÇʵÑéµÄÖ÷Òª²½Ö裺
¢Ù°²×°ºÃÆøµæµ¼¹ì£¬µ÷½ÚÆøµæµ¼¹ìµÄµ÷½ÚÐýÅ¥£¬Ê¹µ¼¹ìˮƽ£»
¢ÚÏòÆøµæµ¼¹ìͨÈëѹËõ¿ÕÆø£»
¢Û°Ñ´òµã¼ÆʱÆ÷¹Ì¶¨ÔÚ½ô¿¿Æøµæµ¼¹ì×ó¶Ëµ¯Éä¼ÜµÄÍâ²à£¬½«Ö½´ø´©¹ý´òµã¼ÆʱÆ÷Ó뵯Éä¼Ü²¢¹Ì¶¨ÔÚ»¬¿é1µÄ×ó¶Ë£¬µ÷½Ú´òµã¼ÆʱÆ÷µÄ¸ß¶È£¬Ö±ÖÁ»¬¿éÍÏ×ÅÖ½´øÒƶ¯Ê±£¬Ö½´øʼÖÕÔÚˮƽ·½Ïò£»
¢Üʹ»¬¿é1¼·Ñ¹µ¼¹ì×ó¶Ëµ¯Éä¼ÜÉϵÄÏðƤÉþ£»
¢Ý°Ñ»¬¿é2·ÅÔÚÆøµæµ¼¹ìµÄÖм䣻
¢ÞÏÈ
½Óͨ´òµã¼ÆʱÆ÷µÄµçÔ´
½Óͨ´òµã¼ÆʱÆ÷µÄµçÔ´
£¬È»ºó
·Å¿ª»¬¿é1
·Å¿ª»¬¿é1
£¬Èû¬¿é´ø¶¯Ö½´øÒ»ÆðÔ˶¯£»
¢ßÈ¡ÏÂÖ½´ø£¬Öظ´²½Öè¢Ü¢Ý¢Þ£¬Ñ¡³öÀíÏëµÄÖ½´øÈçͼbËùʾ£»
¢à²âµÃ»¬¿é1µÄÖÊÁ¿310g£¬»¬¿é2£¨°üÀ¨ÏðƤÄࣩµÄÖÊÁ¿Îª205g£®ÍêÉÆʵÑé²½Öè¢ÞµÄÄÚÈÝ£®
£¨2£©ÒÑÖª´òµã¼ÆʱÆ÷ÿ¸ô0.02s´òÒ»¸öµã£¬¼ÆËã¿ÉÖªÁ½»¬¿éÏ໥×÷ÓÃÒÔǰϵͳµÄ×ܶ¯Á¿Îª
0.620
0.620
kg?m/s£»Á½»¬¿éÏ໥×÷ÓÃÒÔºóϵͳµÄ×ܶ¯Á¿Îª
0.618
0.618
kg?m/s£¨±£ÁôÈýλÓÐЧÊý×Ö£©£®
£¨3£©ÊÔ˵Ã÷£¨2£©ÖÐÁ½½á¹û²»ÍêÈ«ÏàµÈµÄÖ÷ÒªÔ­ÒòÊÇ
Ö½´øÓë´òµã¼ÆʱÆ÷ÏÞλ¿×ÓÐĦ²ÁÁ¦µÄ×÷ÓÃ
Ö½´øÓë´òµã¼ÆʱÆ÷ÏÞλ¿×ÓÐĦ²ÁÁ¦µÄ×÷ÓÃ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø