题目内容
甲、乙两汽车,速度相等,制动后做匀减速运动,甲在3 s内前进18 m停止,乙在制动后1.5 s停止,则乙前进的距离为( )
A.9 m | B.18 m | C.36 m | D.72 m |
A
本题可有多种解法,如用平均速度法,即s=
t,则s甲=
t甲,s乙=
t乙,由
得:s乙="9" m,故A正确.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115905583194.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115905614243.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115905614243.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115905646445.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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题目内容
A.9 m | B.18 m | C.36 m | D.72 m |