题目内容
(8分) 氢原子从-3.4eV的能级跃迁到-0.85eV的能级时,是发射还是吸收光子?这种光子的波长是多少(计算结果取一位有效数字)?图中光电管用金
属材料铯制成,电路中定值电阻R0=0.75Ω,电源电动势E=1.5V,内阻r=0.25Ω,图中电路在D点交
叉,但不相连.R为变阻器,O是变阻器的中间抽头,位于变阻器的正中央,P为滑动端.变阻器的两端点ab总阻值为14Ω.当用上述氢原子两能级间跃迁而发射出来的光照射图中的光电管,欲使电流计G中电流为零,变阻器aP间阻值应为多大?已知普朗克常量h=6.63×10-34J·s,金属铯的逸出功为1.9eV.1eV=1.6×10-19J![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241245265225152.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412452649172.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412452650672.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241245265225152.jpg)
(1)
因氢原子是从低能级向高能级跃迁,故应是吸收光子.
(2)
(3)![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124526616258.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412452660072.gif)
(2)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124526600448.gif)
(3)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124526616258.gif)
略
![](http://thumb2018.1010pic.com/images/loading.gif)
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