题目内容
如图所示,A、B为两平行金属板,板间电压为5v,用波长为
和2
的单色光照射B板时,逸出的光电子的最大初动能分别为30ev和10ev.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241715438742397.jpg)
(1)B金属板的逸出功W为多少电子伏特?
(2)从B板逸出的最大初动能为30ev的所有光电子,因初速度方向不同到达A板的动能是否相同,若相同,为多少?若不同,说明理由?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171543328323.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171543328323.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241715438742397.jpg)
(1)B金属板的逸出功W为多少电子伏特?
(2)从B板逸出的最大初动能为30ev的所有光电子,因初速度方向不同到达A板的动能是否相同,若相同,为多少?若不同,说明理由?
(1)
(2)相同
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171543889675.png)
试题分析:(1)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171544170868.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171544420907.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171544638716.png)
(2)相同,
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171544950720.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171545231693.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824171545590662.png)
点评:本题比较简单,但是涉及物理量比较多,在应用公式的同时要理清物理量之间的关系.
![](http://thumb2018.1010pic.com/images/loading.gif)
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