题目内容
如图甲为测定长木板B在桌面上运动时的加速度的装置.A为沙摆,当沙摆摆动经过平衡位置时开始计时(设为第1次经过平衡位置),当它第30次经过平衡位置时测得所需的时间为29 s.图乙为某次实验在运动的木板上留下的沙子的痕迹,测得数据如图乙所示,则木板的加速度为________m/s2.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036490246025.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036490397351.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036490246025.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250036490397351.jpg)
3.0×10-3
由题图乙可得
x1=0.49 cm x2=0.80 cm
x3=1.09 cm x4=1.40 cm
沙摆周期为T′=
s=2 s,所以T=
=1 s
a1=
=
m/s2
=3.0×10-3 m/s2
a2=
=
m/s2
=3.0×10-3 m/s2
=
=3.0×10-3m/s2
x1=0.49 cm x2=0.80 cm
x3=1.09 cm x4=1.40 cm
沙摆周期为T′=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649055637.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649211428.png)
a1=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649258629.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649289973.png)
=3.0×10-3 m/s2
a2=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649305615.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649320986.png)
=3.0×10-3 m/s2
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649351287.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003649367545.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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