题目内容
如图所示,实线是一列简谐横波在t1 = 0时的波形图,虚线为t2=0.5s时的波形图,已知0<t2-t1<T,t1 = 0时,x=2m处的质点A正向y轴正方向振动。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241638175483017.png)
(1)质点A的振动周期为 ;
(2)波的传播方向是 ;
(3)波速大小为 ;
(4)从t2时刻计时,x=1m处的质点的振动方程是 。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241638175483017.png)
(1)质点A的振动周期为 ;
(2)波的传播方向是 ;
(3)波速大小为 ;
(4)从t2时刻计时,x=1m处的质点的振动方程是 。
①2 s ② 沿着x轴的正方向 ③ 2m/s ④ ![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163817735797.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163817735797.png)
试题分析:(1)根据
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163817922395.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163818172487.png)
(2)已知
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163818562604.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163818718563.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163819061929.png)
(3)波速大小为
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163819279987.png)
(4)t2时刻,
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163819576451.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824163819857536.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241638200911329.png)
点评:根据质点的振动方向判断简谐波的传播方向是学习波动知识应具备的基本功.基础题.
![](http://thumb2018.1010pic.com/images/loading.gif)
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