ÌâÄ¿ÄÚÈÝ

£¨2012?»ÝÖÝһģ£©£¨1£©´òµã¼ÆʱÆ÷ÊÇÁ¦Ñ§Öг£ÓõÄ
¼Æʱ
¼Æʱ
ÒÇÆ÷£¬ÈçͼËùʾ£¬Ä³Í¬Ñ§ÔÚ×ö¡°Ñо¿ÔȱäËÙÖ±ÏßÔ˶¯¡±ÊµÑéÖУ¬ÓÉ´òµã¼ÆʱÆ÷µÃµ½±íʾС³µÔ˶¯¹ý³ÌµÄÒ»ÌõÇåÎúÖ½´ø£¬Ö½´øÉÏÁ½ÏàÁÚ¼ÆÊýµãµÄʱ¼ä¼ä¸ôΪT=0.10s£¬ÆäÖÐx1=7.05cm¡¢x2=7.68cm¡¢x3=8.33cm¡¢x4=8.95cm¡¢x5=9.61cm¡¢x6=10.26cm£¬ÔòAµã´¦Ë²Ê±ËٶȵĴóСÊÇ
0.86
0.86
 m/s£¬Ð¡³µÔ˶¯µÄ¼ÓËٶȼÆËã±í´ïʽΪ
a=
(x4+x5+x6)-(x1+x2+x3)
9T2
a=
(x4+x5+x6)-(x1+x2+x3)
9T2
£¬¼ÓËٶȵĴóСÊÇ
0.64
0.64
 m/s2£¨¼ÆËã½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©£®

£¨2£©Ð¡Ã÷ÉèÏëÓÃÈÈÃôµç×èÖÆ×÷Ò»¸ö¡°Î¶ȼơ±£¬Îª´ËËûÐèÒªÏÈ̽¾¿¸ÃÈÈÃôµç×èµÄ×èÖµËæζȱ仯µÄ¹æÂÉ£®ÏÖÓÐÏÂÁÐÆ÷²Ä£º
´ý²âÈÈÃôµç×èR£¨Ô¼600¡«2000¦¸£©£¬Ö±Á÷ºÁ°²±í£¨Á¿³Ì6mA£¬ÄÚ×èÔ¼0.5¦¸£©£¬
Ö±Á÷µçѹ±í£¨Á¿³Ì3V£¬ÄÚ×èÔ¼1k¦¸£©£¬Ö±Á÷ºãѹµçÔ´£¨Êä³öµçѹ3V£¬ÄÚ×è²»¼Æ£©£¬
»¬¶¯±ä×èÆ÷£¨×èÖµ·¶Î§0¡«500¦¸£©£¬ÒÔ¼°Ë®Òøζȼơ¢¼ÓÈÈ×°Öᢿª¹ØºÍµ¼Ïߣ®

¢ÙӦѡÔñͼ
b
b
£¨a¡¢b£©µÄµç·̽¾¿ÈÈÃôµç×èµÄζÈÌØÐÔ£®
¢ÚÖ÷Òª²½Ö裺¢ÙÁ¬½Óµç·£¬Æô¶¯¼ÓÈÈ×°Ö㬴ýζÈÎȶ¨ÎªÄ³Ò»Î¶Èʱ£¬±ÕºÏ¿ª¹Ø£¬¼ÇÏÂ
ζȼơ¢µçÁ÷±í¡¢µçѹ±íµÄ¶ÁÊý
ζȼơ¢µçÁ÷±í¡¢µçѹ±íµÄ¶ÁÊý
£»¢Ú¸Ä±äζȣ¬¶à´ÎÖظ´²½Öè¢Ù²Ù×÷£¬µÃ³ö¶à×éÊý¾Ý£»¢Û¸ù¾ÝÊý¾Ý¼ÆËãÈÈÃôµç×è×èÖµR£¬»æÖÆRËæζÈt±ä»¯µÄͼÏߣ®£¨3£©ÏÖ½«¸ÃÈÈÃôµç×è¡¢ºãѹµçÔ´¡¢¿ª¹Ø¡¢µ¼Ïß¡¢
µçÁ÷±í
µçÁ÷±í
£¨µçѹ±í¡¢µçÁ÷±í£©Á¬½ÓÆðÀ´£¬°Ñ¸Ãµç±íµÄ¿Ì¶È¸ÄΪÏàÓ¦µÄζȿ̶ȣ¬¾ÍÖƳÉÁËÒ»¸ö¡°Î¶ȼơ±£®ÈôRËæζÈt±ä»¯µÄͼÏßÈçͼc£¬ÔòÓôˡ°Î¶ȼơ±²âµÃµÄζÈÔ½¸ß£¬¶ÔÓ¦Ô­µç±í±íÅ̵Ŀ̶ÈÖµÔ½
С
С
£¨´ó¡¢Ð¡£©£®
·ÖÎö£º±¾Ì⣨1£©µÄ¹Ø¼üÊÇÃ÷È·´òµã¼ÆʱÆ÷µÄ¹¤×÷Ô­ÀíºÍͨ¹ýÖ½´øÇó½â˲ʱËÙ¶ÈÒÔ¼°Ó¦Óá°¶þ·Ö·¨¡±Çó¼ÓËٶȵķ½·¨£»
Ì⣨2£©µÄ¹Ø¼üÊÇÃ÷È··ü°²·¨²âµç×èʱµçÁ÷±íÄÚÍâ½Ó·¨µÄÑ¡Ôñ·½·¨£¬ÒÔ¼°±ÕºÏµç·ŷķ¶¨ÂɵÄÓ¦Óã®
½â´ð£º½â£º£¨1£©´òµã¼ÆʱÆ÷ÊÇÁ¦Ñ§Öг£ÓõļÆʱÒÇÆ÷£¬ÓÉ
x
 
t
2
=
x
t
¿ÉµÃ£¬Aµã˲ʱËٶȴóСΪ
v
 
A
=
x
 
4
+x
 
5
2T
=
(8.95+9.61)¡Á0.01
2¡Á0.01
m/s=0.86m/s£®
ÓÉ¡÷x=a
t
2
 
£¬Óá°¶þ·Ö·¨¡±£¬¿ÉµÃ¼ÓËٶȵıí´ïʽΪa=
(x4+x5+x6)-(x1+x2+x3)
9T2
£¬´úÈëÊý¾Ý½âµÃa=0.64
m
/s
2
 
 
 
£®
£¨2£©¢ÙÓÉÓÚÂú×ã
R
 
x
 
 
R
 
A
£¾
R
 
V
R
 
x
£¬ËùÒÔµçÁ÷±íÓ¦ÓÃÄÚ½Ó·¨£¬¹ÊӦѡµç·b£»
¢ÚÓ¦¼ÇÏÂζȼơ¢µçÁ÷±í¡¢µçѹ±íµÄ¶ÁÊý£»
£¨3£©ÓÉÓÚµçÁ÷±íÓëÈÈÃôµç×è´®Áª£¬ËùÒÔÓ¦½«¸ÃÈÈÃôµç×è¡¢ºãѹµçÔ´¡¢¿ª¹Ø¡¢µ¼Ïß¡¢µçÁ÷±íÁ¬½ÓÁ¬½ÓÆðÀ´£»
ÓÉR-t¡ãͼÏó¿´³öζÈÉý¸ßµç×èÔö´ó£¬ÓÉI=
E
R
 
×Ü
¿ÉÖª£¬µçÁ÷±íµÄʾÊý¼õС£¬ËùÒÔ´Ë¡°Î¶ȼơ±²âµÃµÄζÈÔ½¸ß£¬¶ÔÓ¦Ô­µç±í±íÅ̵Ŀ̶ÈֵԽС£®
¹Ê´ð°¸Îª£º£¨1£©¼Æʱ£¬0.86£¬a=
(x4+x5+x6)-(x1+x2+x3)
9T2
£¬0.64£»
         £¨2£©¢Ùb£¬Î¶ȼơ¢µçÁ÷±í¡¢µçѹ±íµÄ¶ÁÊý£¬µçÁ÷±í£¬Ð¡£®
µãÆÀ£ºÃ÷ȷʵÑéÔ­ÀíºÍʵÑé·½·¨ÊÇÇó½âʵÑéÎÊÌâµÄ¹Ø¼ü£¬ÔÚÓйصçѧʵÑéÖУ¬ÒªÃ÷È··ü°²·¨ÖеçÁ÷±íÄÚÍâ½Ó·¨ÒÔ¼°±ä×èÆ÷²ÉÓ÷Öѹʽ»¹ÊÇÏÞÁ÷ʽ½Ó·¨µÄÑ¡Ôñ·½·¨£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø