题目内容
如图所示,弹簧振子在振动过程中,经过a、b两点的速度相同,历时0.2s。从b点再回到a的最短时间为0.4s,则该振子的振动频率为( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241403050961532.jpg)
A.1Hz | B.1.25Hz |
C.2Hz | D.2.5Hz |
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241403050961532.jpg)
B
a b关于O点对称,振子一个周期的时间为
,由题意可得
,因为
,所以
,由对称可得
,所以
,根据公式
,所以振子的振动频率为1.25HZ,选B。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305111827.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305158600.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305205843.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305283550.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305377526.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305455502.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824140305501466.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目
题目内容
A.1Hz | B.1.25Hz |
C.2Hz | D.2.5Hz |