题目内容
如图所示,透明介质球球心位于O,半径为R,光线DC平行于直径AOB射到介质球的C点,DC与AB的距离H=
R,若DC光线进入介质球后经一次反射再次回到介质球的界面时,从球内折射出的光线与入射光线平行,作出光路图,并计算出介质的折射率.
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250045588166592.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004558784453.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250045588166592.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004558831448.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/2014082500455884711111.jpg)
试题分析:光路图如图(见答案),
光线经反射后到达介质与空气的界面时,入射角θ3=θ2,由折射定律可得折射角θ4=θ1,折射光线PQ与入射光线DC平行,则∠POA=∠COA=θ1,sin θ1=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004558878657.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004558972338.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004558987872.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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