题目内容
半径为
和
的圆柱体靠摩擦传动,已知
,
分别在小圆柱与大圆柱的边缘上,
是圆柱体上的一点,
,如图所示,若两圆柱之间没有打滑现象,则A,B,C三者的向心加速度之比 aA∶aB∶aC = 。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242049187811787.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204913743260.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204914304303.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204915100463.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204916114419.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204916863313.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204917814514.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242049187811787.png)
4 : 2 : 1
试题分析:传动过程中,两圆柱之间没有打滑现象,说明A、B两点的线速度相等,即vA=vB,由
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204920123547.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824204920887580.png)
点评:解决本题的关键知道靠传送带传动轮子边缘上的点具有相同的线速度,共轴转动的点,具有相同的角速度
![](http://thumb2018.1010pic.com/images/loading.gif)
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