题目内容
(7分)一列简谐横波由波源O点沿x轴正方向传播, OA= 0.4m,AB=0.6m,经时间4×10-2s,振动从O点传播到了A点,此时波形如图所示。当这列波进入AB区域时,它的传播速度变为原来的1.5倍,那么:
(1)这列波在OA和AB区域的波长分别是多少?
(2)从图示时刻起,经过多长时间,质点B第三次到达正向最大位移处?![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241215176687831.gif)
(1)这列波在OA和AB区域的波长分别是多少?
(2)从图示时刻起,经过多长时间,质点B第三次到达正向最大位移处?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241215176687831.gif)
(1)OA段:
;OB段:![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517699441.gif)
(2)9.5x10-2 s
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517683441.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517699441.gif)
(2)9.5x10-2 s
(1)由题意:周期T=2x10-2s (1分)OA段:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517714438.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517730598.gif)
OB段:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517730747.gif)
(2)波从A传到B需要时间:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517746609.gif)
再经
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824121517761660.gif)
所以 t=t1+t2=9.5x10-2 s (1分)
![](http://thumb2018.1010pic.com/images/loading.gif)
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