题目内容
某同学用弹簧测力计水平拉着质量为
的木板在水平桌面上向右匀速运动,读出测力计的示数为
试求:
(1)木板受到桌面的滑动摩擦力大小; ☆
(2)木板与桌面间的动摩擦因数。(取
。)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416780456.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416795422.gif)
(1)木板受到桌面的滑动摩擦力大小; ☆
(2)木板与桌面间的动摩擦因数。(取
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416811474.gif)
2.8N 0.28
(1)木板在水平桌面做匀速直线运动,受到的滑动摩擦力和拉力平衡,所以木板受到桌面的滑动摩擦力大小
=2.8N
(2)根据滑动摩擦力的计算公式:
及
可求出
=0.28
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416827199.gif)
(2)根据滑动摩擦力的计算公式:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416842408.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416842405.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115416873204.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目