题目内容
如图所示,一质量为m的物体,在倾角为θ的斜面上匀速下滑,求
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745697423.png)
(1)物体对斜面的压力;
(2)物体与斜面间的动摩擦因数。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745697423.png)
(1)物体对斜面的压力;
(2)物体与斜面间的动摩擦因数。
(1)N=mgcosθ
(2)μ=tanθ
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241237459006968.png)
解:(1)根据题意,对斜面上的物体受力分析如上图所示,由于物体在斜面上匀速下滑,可知沿斜面水平方向上物体所受合外力为零,即f=G1=mg
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745916426.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745947375.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745962430.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745962430.png)
(2)由于物体在斜面上匀速下滑,受到斜面对它的摩擦力为f,物体对斜面的压力F= mg
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745962430.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123746072824.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824123745916426.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241237461181272.png)
【答案小结】
(1)N=mgcosθ
(2)μ=tanθ
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目