ÌâÄ¿ÄÚÈÝ

Èçͼ1Ëùʾ£¬Ò»¶Ô×ã¹»³¤µÄƽÐй⻬µ¼¹ì·ÅÖÃÔÚˮƽÃæÉÏ£¬Á½¹ìµÀ¼ä¾àl=0.20m£¬¶¨Öµµç×è×èÖµR=1.0¦¸£®ÓÐÒ»½ðÊô¸Ë¾²Ö¹µØ·ÅÔÚ¹ìµÀÉÏ£¬ÓëÁ½¹ìµÀ´¹Ö±ÇÒ½Ó´¥Á¼ºÃ£¬½ðÊô¸ËÓë¹ìµÀµÄµç×è½Ô¿ÉºöÂÔ²»¼Æ£¬Õû¸ö×°Öô¦ÓڴŸÐӦǿ¶ÈΪB=0.50TµÄÔÈÇ¿´Å³¡ÖУ¬´Å³¡·½Ïò´¹Ö±¹ìµÀÃæÏòÏ£®ÏÖÓÃÒ»ÍâÁ¦FÑعìµÀ·½ÏòÀ­¸Ë£¬Ê¹Ö®×öÔȼÓËÙÔ˶¯£¬²âµÃÁ¦FÓëʱ¼ätµÄ¹ØϵÈçͼ2Ëùʾ£®Çó£º


(1)¸ËµÄÖÊÁ¿mºÍ¼ÓËÙ¶È
(2)Ôڸ˴Ӿ²Ö¹¿ªÊ¼Ô˶¯µÄ20sµÄʱ¼äÄÚ£¬Í¨¹ýµç×èRµÄµçÁ¿£®
 
£¨1£©0.1kg £¬10m/s2£¨2£©200C

(1)ÒÔ½ðÊô¸ËΪÑо¿¶ÔÏ󣬵ç´Å¸ÐÓ¦¶¨ÂÉ¡¢Å£¶ÙÔ˶¯¶¨ÂɺÍÔȼÓËÙÔ˶¯¹«Ê½£¬²¢½áºÏ±ÕºÏµç·ŷķ¶¨ÂÉ£¬ÓÐ

F¨CIlB=ma
v=at
¡à£®
ÓÉͼÏßÉÏÈ¡Á½µã×ø±ê(0s£¬1N)ºÍ(20s£¬3N)´úÈë·½³Ì
½âµÃ£ºa=10m/s2£»m=0.1kg
(2)Ôڸ˴Ӿ²Ö¹¿ªÊ¼Ô˶¯µÄ20sµÄʱ¼äÄÚ£¬¸ù¾Ý·¨À­µÚµç´Å¸ÐÓ¦¶¨ÂÉ£¬ÓÐ

ËùÒÔ£¬Í¨¹ýµç×èRµÄµçÁ¿200C
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø