题目内容
(11分)如图11所示,两根电阻忽略不计的平行光滑金属导轨ab、cd置于匀强磁场中,磁场方向垂直纸面向里,两导轨间的距离L=0.6m。电阻R=2Ω,金属杆MN阻值r=1Ω,当用外力F拉着金属杆MN沿两条导轨向右匀速滑动,速度v=10m/s,产生
的感应电动势为3V。求:
(1)磁场的磁感应强度B为多少?
(2)导体杆MN所受的拉力多大?![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241246347105732.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082412463466372.gif)
(1)磁场的磁感应强度B为多少?
(2)导体杆MN所受的拉力多大?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241246347105732.jpg)
(1)B=0.5T(2)![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241246347251087.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241246347251087.jpg)
(11分)
(1)根据法拉第电磁感应定律
(2分)
得:B="0.5T " (2分)
(2)根据闭合电路欧姆定律
(2分)
得:
(1分)
ab杆所受安培力:
(2分)
得:
(1分)
ab杆所受拉力与安培力平衡,即
=" 0.3N " (1分)
(1)根据法拉第电磁感应定律
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124634741302.gif)
得:B="0.5T " (2分)
(2)根据闭合电路欧姆定律
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124634757450.gif)
得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124634772268.gif)
ab杆所受安培力:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124635115325.gif)
得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124635131452.gif)
ab杆所受拉力与安培力平衡,即
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124635147269.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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