ÌâÄ¿ÄÚÈÝ

»¬°åÔ˶¯ÊÇÒ»ÏÏմ̼¤µÄÔ˶¯£¬ÉîÊÜÇàÉÙÄêµÄϲ°®£®ÈçͼÊÇ»¬°åÔ˶¯µÄ¹ìµÀ£¬ABºÍCDÊÇÒ»¶ÎÔ²»¡ÐιìµÀ£¬BCÊÇÒ»¶Î³¤7mµÄˮƽ¹ìµÀ£®Ò»Ô˶¯Ô±´ÓAB¹ìµÀÉÏPµãÒÔ6m/sµÄËÙ¶ÈÏ»¬£¬¾­BC¹ìµÀºó³åÉÏCD¹ìµÀ£¬µ½QµãʱËٶȼõΪÁ㣮ÒÑÖªÔ˶¯Ô±µÄÖÊÁ¿50kg£¬h=1.4m£¬H=1.8m£¬²»¼ÆÔ²»¡¹ìµÀÉϵÄĦ²Á£®£¨g=10m/s2£©Çó£º
£¨1£©Ô˶¯Ô±µÚÒ»´Î¾­¹ýBµãʱµÄËÙ¶ÈÊǶàÉÙ£¿
£¨2£©Ô˶¯Ô±ÓëBC¹ìµÀµÄ¶¯Ä¦²ÁÒòÊý£®
£¨3£©Ô˶¯Ô±×îºóÍ£ÔÚBC¹ìµÀÉϾàBΪ¶àÉÙÃ×´¦£¿
·ÖÎö£º£¨1£©Ô˶¯Ô±´ÓPµã»¬ÖÁBµãʱ£¬Ö»ÓÐÖØÁ¦×ö¹¦£¬¸ù¾Ý¶¯Äܶ¨Àí»ò»úеÄÜÊغãÇó½âÔ˶¯Ô±µÚÒ»´Î¾­¹ýBµãʱµÄËٶȣ»
£¨2£©Ô˶¯Ô±ÓÉP»¬ÖÁD¹ý³ÌÖУ¬ÔËÓö¯Äܶ¨ÀíÇó½â¶¯Ä¦²ÁÒòÊý£®
£¨3£©Ô˶¯Ô±×îÖÕÍ£ÔÚBCÉÏ£¬¶ÔÕû¸ö¹ý³Ì£¬¸ù¾Ý¶¯Äܶ¨ÀíÇó½âÔ˶¯Ô±ÔÚBC»¬ÐеÄ×Ü·³Ì£¬¼´¿ÉÈ·¶¨×îºóÍ£ÔÚBCÉϵÄλÖã®
½â´ð£º½â£º£¨1£©Ô˶¯Ô±´ÓPµã»¬ÖÁBµãʱ£¬Óɶ¯Äܶ¨ÀíÓÐ
    mgh=
1
2
m
v
2
B
-
1
2
m
v
2
0

½âµÃÔ˶¯Ô±ÔÚBµãʱµÄËٶȠ vB=8m/s
£¨2£©Ô˶¯Ô±ÓÉP»¬ÖÁD¹ý³ÌÖУ¬Óɶ¯Äܶ¨ÀíÓÐ
   -mg(H-h)-¦Ìmgl=-
1
2
m
v
2
0

½âµÃÔ˶¯Ô±ÓëBC¼äµÄ¶¯Ä¦²ÁÒòÊý ¦Ì=0.2
£¨3£©ÉèÔ˶¯Ô±ÔÚBCÃæÉÏ»¬ÐеÄ×Ü·³ÌΪs£¬´ÓPµã¿ªÊ¼Ô˶¯µ½×îºóÍ£Ö¹£¬
ÓÉÄÜÁ¿ÊغãÓР ¦Ìmgs=
1
2
m
v
2
0
+mgh

½âµÃ  s=16m    
ÓÉÓÚBC=7m£¬ËùÒÔ×îºóÍ£Ö¹µÄλÖþàÀëBµãΪ2m   
´ð£º£¨1£©Ô˶¯Ô±µÚÒ»´Î¾­¹ýBµãʱµÄËÙ¶ÈÊÇ8m/s£®
£¨2£©Ô˶¯Ô±ÓëBC¹ìµÀµÄ¶¯Ä¦²ÁÒòÊýÊÇ0.2£®
£¨3£©Ô˶¯Ô±×îºóÍ£ÔÚBC¹ìµÀÉϾàBΪ2m´¦£®
µãÆÀ£º±¾ÌâÔËÓö¯Äܶ¨Àíʱ£¬¹Ø¼üÊÇÁé»îÑ¡ÔñÑо¿µÄ¹ý³Ì£¬Òª×¥×¡»¬¶¯Ä¦²ÁÁ¦×ö¹¦Óë×Ü·³ÌÓйأ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø