题目内容
如图为一质点沿直线运动的
图像,已知质点从零时刻出发,在2T时刻恰好返回出发点。则下列说法正确的是
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250032395171550.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239470356.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250032395171550.png)
A.0~T与T~2T时间内的位移相同 |
B.质点在1.5T时离出发点最远 |
C.T秒末与2T秒末速度大小之比为1:2 |
D.0~T与T~2T时间内的加速度大小之比为1:3 |
CD
试题分析: 0~T与T~2T时间内的初、末位置恰好相反,故位移方向相反,故A错误;当速度为零时,质点离出发点最远,显然与图象矛盾,故B错误;设T时刻速度为v1,2T时刻速度为v2,0~T与T~2T时间内的位移相反,故:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239533516.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239548538.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239564497.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239595411.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239611531.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003239626518.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目