题目内容
某汽车以速度10m/s匀速行驶,刹车后第1个2s内位移与最后一个2s内位移之比为3∶2,设卡车做匀减速直线运动,则刹车后4s内卡车通过的距离是
A.2.5m | B.4m | C.12m | D.12.5m |
D
试题分析:设加速度的大小为a,则第1个2s内的位移
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001615030958.png)
根据逆向思维,最后1个2s内的位移
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001615046964.png)
根据
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001615062869.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001615093622.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001615108709.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250016151241097.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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题目内容
A.2.5m | B.4m | C.12m | D.12.5m |