ÌâÄ¿ÄÚÈÝ
ÔÚÑéÖ¤»úеÄÜÊغ㶨ÂɵÄʵÑéÖÐ
¢ÅʵÑéÊÒÖб¸ÓÐÏÂÊöÆ÷²Ä£ºAÌú¼Ų̈¡¢B´òµã¼ÆʱÆ÷¡¢CÌìƽ¡¢Dµ¯»É³Ó¡¢EÖ½´ø¡¢F´ø¼Ð×ÓµÄÖØÎï¡¢G¿Ì¶È³ß¡¢HÃë±í£¬ÆäÖÐʵÑéÐèÒªÓõ½µÄÓÐÄÄЩÆ÷²Ä___________¡££¨Ìî×Öĸ£©
¢Æ×ö´ËʵÑéʱ£¬ÓÐͬѧ°´ÒÔϲ½Öè½øÐÐ
¢ÙÓÃÌìƽ³Æ³öÎïÌåµÄÖÊÁ¿
¢Ú¹Ì¶¨ºÃ´òµã¼ÆʱÆ÷£¬½«Á¬ÓÐÖØÎïµÄÖ½´ø´©¹ýÏÞλ¿×£¬ÓÃÊÖÌáסֽ´øÄ©¶Ë£¬ÈÃÊÖ¾¡Á¿¿¿½ü´òµã¼ÆʱÆ÷
¢ÛÏȽÓͨµçÔ´£¬ÔÙËÉ¿ªÖ½´ø£¬¿ªÊ¼´òµã£¬²¢Èç´ËÖظ´¼¸´Î£¬È¡µÃ¼¸Ìõ´òµãÖ½´ø
¢ÜÈ¡ÏÂÖ½´ø£¬ÌôÑ¡µã¼£Çå³þµÄÖ½´ø£¬¼ÇÏÂÆðʼµãO£¬ÔÚÀëOµãÊʵ±¾àÀ봦ѡÔñ¼¸¸öÁ¬ÐøµÄ¼ÆÊýµã£¨»ò¼Æʱµã£©²¢¼ÆËã³ö¸÷¸öµãµÄËÙ¶ÈÖµ
¢Ý²â³ö¸÷µã¾àOµãµÄ¾àÀ룬¼´Îª¶ÔÓ¦µÄÏÂÂä¸ß¶È
¢Þ¼ÆËã³öºÍ£¬¿´ÊÇ·ñÏàµÈ
ÔÚÉÏÊö²½ÖèÖУ¬ÓÐÒ»Ïî¶àÓàµÄ²½ÖèÊÇ___________£¬£¨ÌîÐòºÅ£©
ÔÚÉÏÊö²½ÖèÖУ¬ÓÐÒ»Ïî´íÎóµÄ²½ÖèÊÇ £¨ÌîÐòºÅ£©¸üÕýΪ £»
¢ÇÈôÒÑÖªÖØ´¸µÄÖÊÁ¿Îª1kg£¬ÔÚʵÑéÖдò³öµÄÖ½´øÈçͼËùʾ£¬ÆäÖÐOµãΪÖØ´¸¾²Ö¹Ê±´òµã¼ÆʱÆ÷´òϵĵÚÒ»¸öµã£¬A¡¢B¡¢CΪij¶ÎÖм¸¸ö½ÏÇåÎúµÄÏàÁڵ㣬´òµãʱ¼ä¼ä¸ôΪ0.02s¡£¾¹ý²âÁ¿µÃµ½OA=18.0cm£¬OB=21.5cm£¬OC=26.0cm¡£²é³öµ±µØµÄÖØÁ¦¼ÓËÙ¶Èg=9.80m/s2£¬ÔòÖØÎïÔÚBµãʱµÄ¶¯ÄÜÊÇ J¡£´Ó¿ªÊ¼ÏÂÂäµ½BµãµÄ¹ý³ÌÖУ¬ÖØÎïµÄÖØÁ¦ÊÆÄܼõÉÙÁ¿ÊÇ J£¬£¨¾ù±£Áô3λÓÐЧÊý×Ö£©Óɴ˵óöµÄ½áÂÛÊÇ ¡£
¢ÅʵÑéÊÒÖб¸ÓÐÏÂÊöÆ÷²Ä£ºAÌú¼Ų̈¡¢B´òµã¼ÆʱÆ÷¡¢CÌìƽ¡¢Dµ¯»É³Ó¡¢EÖ½´ø¡¢F´ø¼Ð×ÓµÄÖØÎï¡¢G¿Ì¶È³ß¡¢HÃë±í£¬ÆäÖÐʵÑéÐèÒªÓõ½µÄÓÐÄÄЩÆ÷²Ä___________¡££¨Ìî×Öĸ£©
¢Æ×ö´ËʵÑéʱ£¬ÓÐͬѧ°´ÒÔϲ½Öè½øÐÐ
¢ÙÓÃÌìƽ³Æ³öÎïÌåµÄÖÊÁ¿
¢Ú¹Ì¶¨ºÃ´òµã¼ÆʱÆ÷£¬½«Á¬ÓÐÖØÎïµÄÖ½´ø´©¹ýÏÞλ¿×£¬ÓÃÊÖÌáסֽ´øÄ©¶Ë£¬ÈÃÊÖ¾¡Á¿¿¿½ü´òµã¼ÆʱÆ÷
¢ÛÏȽÓͨµçÔ´£¬ÔÙËÉ¿ªÖ½´ø£¬¿ªÊ¼´òµã£¬²¢Èç´ËÖظ´¼¸´Î£¬È¡µÃ¼¸Ìõ´òµãÖ½´ø
¢ÜÈ¡ÏÂÖ½´ø£¬ÌôÑ¡µã¼£Çå³þµÄÖ½´ø£¬¼ÇÏÂÆðʼµãO£¬ÔÚÀëOµãÊʵ±¾àÀ봦ѡÔñ¼¸¸öÁ¬ÐøµÄ¼ÆÊýµã£¨»ò¼Æʱµã£©²¢¼ÆËã³ö¸÷¸öµãµÄËÙ¶ÈÖµ
¢Ý²â³ö¸÷µã¾àOµãµÄ¾àÀ룬¼´Îª¶ÔÓ¦µÄÏÂÂä¸ß¶È
¢Þ¼ÆËã³öºÍ£¬¿´ÊÇ·ñÏàµÈ
ÔÚÉÏÊö²½ÖèÖУ¬ÓÐÒ»Ïî¶àÓàµÄ²½ÖèÊÇ___________£¬£¨ÌîÐòºÅ£©
ÔÚÉÏÊö²½ÖèÖУ¬ÓÐÒ»Ïî´íÎóµÄ²½ÖèÊÇ £¨ÌîÐòºÅ£©¸üÕýΪ £»
¢ÇÈôÒÑÖªÖØ´¸µÄÖÊÁ¿Îª1kg£¬ÔÚʵÑéÖдò³öµÄÖ½´øÈçͼËùʾ£¬ÆäÖÐOµãΪÖØ´¸¾²Ö¹Ê±´òµã¼ÆʱÆ÷´òϵĵÚÒ»¸öµã£¬A¡¢B¡¢CΪij¶ÎÖм¸¸ö½ÏÇåÎúµÄÏàÁڵ㣬´òµãʱ¼ä¼ä¸ôΪ0.02s¡£¾¹ý²âÁ¿µÃµ½OA=18.0cm£¬OB=21.5cm£¬OC=26.0cm¡£²é³öµ±µØµÄÖØÁ¦¼ÓËÙ¶Èg=9.80m/s2£¬ÔòÖØÎïÔÚBµãʱµÄ¶¯ÄÜÊÇ J¡£´Ó¿ªÊ¼ÏÂÂäµ½BµãµÄ¹ý³ÌÖУ¬ÖØÎïµÄÖØÁ¦ÊÆÄܼõÉÙÁ¿ÊÇ J£¬£¨¾ù±£Áô3λÓÐЧÊý×Ö£©Óɴ˵óöµÄ½áÂÛÊÇ ¡£
£¨1£©ABEFG £¨2£©¶àÓàµÄ¢Ù ´íÎóµÄ¢Ú ¸üÕýΪÈÃÊÖ¾¡Á¿Ô¶Àë´òµã¼ÆʱÆ÷ ¢Ç¶¯ÄÜ2.00J ÖØÁ¦ÊÆÄܼõÉÙÁ¿2.06 J ½áÂÛÊÇ ÔÚÎó²î·¶Î§ÄÚ£¬ÖØÎïµÄÖØÁ¦ÊÆÄܼõÉÙÓ붯ÄÜÔö¼ÓÁ¿ÏàµÈ£¬ËùÒÔ»úеÄÜÊغ㠡£
ÊÔÌâ·ÖÎö£ºÊÔÌâ·ÖÎö£º¢ÅʵÑéÇ°ÐèÒª°Ñ´òµã¼ÆʱÆ÷¹Ì¶¨ÔڽϸßλÖã¬ËùÒÔÒªÓÃÌú¼Ų̈£»¼Ç¼µã¼£ÐèÒªÖ½´ø£»ÐèÒªÖØÎïÀ¶¯Ö½´øÔ˶¯£¬ÇÒÖ½´øÐèÒª¼Ð×ӹ̶¨£»µã¼£Ö®¼äµÄ¾àÀëÐèÒª¿Ì¶È³ß²âÁ¿¡£¢Æ¾Ýmghn=mvn2/2£¬ÖÊÁ¿¿ÉÒÔÏûÈ¥£¬ËùÒÔ²»ÐèÒª²âÁ¿ÖØ´¸ÖÊÁ¿£»ÊÍ·ÅÖ½´øÇ°ÒªÈÃÊÖ¾¡Á¿Ô¶Àë´òµã¼ÆʱÆ÷²Å¿ÉÒÔÔÚÖ½´øÉÏ´òϽ϶àµÄµã¼£¡£¢ÇBµãµÄ¶¯ÄÜΪEKB=mvB2/2£¬¶øvB=LAC/2=2m/s£¬ÔòEKB=2.00J£»ÖØ´¸ÏÂÂäµÄÖØÁ¦ÊÆÄÜΪEPB=mgLOB=2.08J£¬ÔÚʵÑéÎó²îÔÊÐí´æÔÚµÄÇé¿öÏ£¬ÖØ´¸ÏÂÂäµÄÖØÁ¦ÊÆÄÜÓëÖØ´¸Ôö¼ÓµÄ¶¯ÄÜÏàµÈ£¬ÖØ´¸»úеÄÜÊغ㡣
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿