ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿£¨1£©Ð¡Çò×öÖ±ÏßÔ˶¯Ê±µÄƵÉÁÕÕƬÈçͼËùʾ¡£ÒÑ֪ƵÉÁÖÜÆÚT=0.1s£¬Ð¡ÇòÏàÁÚλÖüä¾à(ÓÉÕÕƬÖеĿ̶ȳßÁ¿µÃ)·Ö±ðÊÇOA=5.19cm AB=4.40cm BC=3.59cm ¡¡CD=2.80cm DE=2.01cm EF=1.21cm.ÔòСÇòÔÚλÖÃBʱµÄËٶȴóСvB= ________m/s£»Ð¡ÇòÔ˶¯µÄ¼ÓËٶȴóСa=_____________m/s2¡£(½á¹û¾ù±£ÁôÁ½Î»ÓÐЧÊý×Ö)

£¨2£©ÀûÓÃͼÖÐËùʾµÄ×°Öã¬ÔÚ×ö¡°²âÁ¿ÖØÁ¦¼ÓËٶȡ±µÄʵÑéÖУ¬µÃµ½Á˼¸Ìõ½ÏΪÀíÏëµÄÖ½´ø¡£ÒÑ֪ÿÌõÖ½´øÉÏÿ5¸öµãÈ¡Ò»¸ö¼ÆÊýµã£¬¼´Á½¼ÆÊýµãÖ®¼äµÄʱ¼ä¼ä¸ôΪ0.1s£¬ÒÀ´òµãÏȺó±àΪ0£¬1£¬2£¬3£¬4£¬¡­¡­¡£ÓÉÓÚ²»Ð¡ÐÄ£¬Ö½´ø¶¼±»Ëº¶ÏÁË£¬ÈçͼËùʾ£¬¸ù¾Ý¸ø³öµÄA¡¢B¡¢C¡¢DËĶÎÖ½´ø»Ø´ð£º

¢ÙÔÚB¡¢C¡¢DÈý¶ÎÖ½´øÖÐÑ¡³ö´ÓÖ½´øAÉÏ˺ϵÄÄǶÎÓ¦¸ÃÊÇ______ £¨Ìî×Öĸ£©

¢ÚÖ½´øAÉÏ£¬´òµã1ʱÖØÎïµÄËÙ¶ÈÊÇ_________ m/s£¨½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©¡£

¢Ûµ±µØµÄÖØÁ¦¼ÓËٶȴóСÊÇ_________ m/s2£¨½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©¡£¸ÃµØÇøµÄµØÐοÉÄÜΪ_______________ £¨Ìî¡°¸ßɽ¡±»ò¡°ÅèµØ¡±£©¡£

¡¾´ð°¸¡¿£¨1£©0.40m/s£º0.80m/s2£¨2£©¢ÙC¢Ú3.47m/s¢Û9.00m/s2£» ¸ßɽ

¡¾½âÎö¡¿

£¨1£©ÉèOA=x1£¬AB=x2£¬BC=x3£¬CD=x4£¬DE=x5£¬EF=x6£®Ôò¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯ÖÐʱ¼äÖеãµÄ˲ʱËٶȵÈÓڸùý³ÌÖеÄƽ¾ùËÙ¶ÈÓÐСÇòÔÚBÖõÄËٶȣºvB£½£½0.40m/s
¸ù¾Ý¡÷x=aT2ÓУºx4-x1=3a1T2£¬x5-x2=3a2T2£¬x6-x3=3a3T2£¬µÃµ½=0.80m/s2£¬ÔòСÇòÔ˶¯µÄ¼ÓËٶȴóС0.80m/s2

£¨2£©¢Ù¡÷x=x12-x01=39.2cm-30.2cm=9cm£»x34=x12+2¡÷x=39.2cm+2¡Á9cm=57.2cm£»¹ÊÑ¡C£»
¢ÚÔȱäËÙÖ±ÏßÔ˶¯Ä³¶Îʱ¼äÖмä˲ʱËٶȣ¬¹Ê

¢ÛÓÉ¡÷x=aT2£¬µÃµ½£º
ÖØÁ¦¼ÓËÙ¶ÈÓë¸ß¶ÈºÍγ¶ÈÓйأ¬¹ÊÒ»¶¨ÊÇÔÚ¸ßɽÉÏ£»

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø