ÌâÄ¿ÄÚÈÝ
Èçͼ¼×Ëùʾ£¬Á½Æ½ÐнðÊô°å¼ä´æÔÚÏ໥´¹Ö±µÄµç³¡ºÍ´Å³¡£¬Á½½ðÊô°å¼äµÄµçѹΪU£¬°å¼ä¾àÀëΪd£¬Á½°å¼äµÄ´Å³¡ÔÚ3t0Äڵı仯¹æÂÉÈçͼÒÒËùʾ. ×ó²àµÄÁ£×ÓÔ´ÑØÖÐÐÄÏßOO¡¯ÒÔv0µÄËٶȲ»¶Ï·¢ÉäÖÊÁ¿Îªm¡¢µçºÉÁ¿Îª+qµÄÁ£×Ó£¨²»¼ÆÖØÁ¦£©. ÒÑÖªt=0ʱ¿Ì½øÈëÁ½°å¼äµÄ´øµçÁ£×Ó£¬Ç¡ºÃÑØÖÐÐÄÏßÔ˶¯£¬²¢ÔÚt0ʱ¿Ì´ÓO¡¯µã´©³öÁ½°å.
£¨1£©Çó´Å¸ÐӦǿ¶ÈB0µÄ·½ÏòºÍ´óС£»
£¨2£©Èôt0ʱ¿Ì½øÈëÁ½°å¼äµÄÁ£×ÓÒ²ÄÜ´Ó°å¼ä·É³ö£¬Çó·É³öʱƫÀëO¡¯µãµÄ¾àÀë.
£¨1£©Çó´Å¸ÐӦǿ¶ÈB0µÄ·½ÏòºÍ´óС£»
£¨2£©Èôt0ʱ¿Ì½øÈëÁ½°å¼äµÄÁ£×ÓÒ²ÄÜ´Ó°å¼ä·É³ö£¬Çó·É³öʱƫÀëO¡¯µãµÄ¾àÀë.
(1) B0= (2) y=
ÊÔÌâ·ÖÎö£º£¨1£©´øµçÁ£×ÓÊܵĵ糡Á¦ÊúÖ±ÏòÏ£¬ÔòÂåÂ××ÈÁ¦µÄ·½ÏòÊúÖ±ÏòÉÏ£¬ÓÉ×óÊÖ¶¨Ôò¿ÉÅжϳö´Å¸ÐӦǿ¶ÈµÄ·½Ïò´¹Ö±Ö½ÃæÏòÀï¡£ £¨2·Ö£©
´øµçÁ£×ÓÑØÖÐÐÄÏß×öÔÈËÙÖ±ÏßÔ˶¯£¬ÓÐqv0B0=q £¨1·Ö£©
Ôò´Å¸ÐӦǿ¶ÈµÄ´óСΪB0= £¨1·Ö£©
£¨2£©´Ót0ʱ¿Ì½øÈëÁ½°å¼äµÄ´øµçÁ£×Ó£¬ÔÚt0ʱ¼äÄÚ×öÔÈËÙÖ±ÏßÔ˶¯£¬È»ºóÔڵ糡Á¦µÄ×÷ÓÃÏÂ×öÀàƽÅ×Ô˶¯¡£
Á£×Ó×öÀàƽÅ×Ô˶¯µÄʱ¼äΪt=t0 £¨1·Ö£©
ÊúÖ±·½ÏòÓÐy=at2 £¨1·Ö£©
ÓÉÅ£¶ÙµÚ¶þ¶¨ÂɵÃa= £¨1·Ö£©
½âµÃy= £¨1·Ö£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿