ÌâÄ¿ÄÚÈÝ

4£®Èçͼ¼×Ëùʾ£¬µçÔ´µÄµç¶¯ÊÆE=9V£¬ËüºÍÁéÃôµçÁ÷±íGµÄÄÚ×è¾ù²»¿ÉºöÂÔ£¬µçѹ±íVµÄÄÚ×èºÜ´ó£¬ÈÈÃôµç×èRµÄ×èÖµËæζȵı仯¹ØϵÈçͼÒÒËùʾ£®±ÕºÏ¿ª¹ØS£¬µ±RµÄζȵÈÓÚ20¡æʱ£¬µçÁ÷±íʾÊýI1=2mA£®¸ù¾ÝÒÔÉÏÐÅÏ¢Åжϣ¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®µçÁ÷±íÄÚ×èÓëµçÔ´ÄÚ×èÖ®ºÍΪ0.5k¦¸
B£®µçÁ÷±íʾÊýI2=3.6mAʱÈÈÃôµç×èµÄζÈÊÇ100¡æ
C£®Î¶ÈÉý¸ßʱµçѹ±íʾÊýUÓëµçÁ÷±íʾÊýIµÄ±ÈÖµ±ä´ó
D£®Î¶ÈÉý¸ßʱµçѹ±íʾÊý±ä»¯Á¿¡÷UÓëµçÁ÷±íʾÊý±ä»¯Á¿¡÷IµÄ±ÈÖµ¼õС

·ÖÎö ±ÕºÏ¿ª¹ØS£¬µ±RµÄζȵÈÓÚ20¡æʱ£¬µçÁ÷±íʾÊýI1=2mA£¬¸ù¾Ý±ÕºÏµç·ŷķ¶¨ÂÉ¿ÉÇóµÃµçÁ÷±íÓëµçÔ´µÄÄÚ×èÖ®ºÍRÄÚ£»
µ±µçÁ÷±íµÄʾÊýI2=3.6mAʱ£¬¸ù¾Ý±ÕºÏµç·ŷķ¶¨ÂÉ¿ÉÇóR£¬ÓÉͼ¶Á³öζȣ®

½â´ð ½â£ºA¡¢ÒÑÖª£ºµçÔ´µçÔ´µÄµç¶¯ÊÆE=9.0V£¬I1=2mA=0.002A£¬I2=3.6mA=0.0036A£»
ÓÉͼÏóÖª£¬µ±RµÄζȵÈÓÚ20¡æʱ£¬ÈÈÃôµç×èµÄ×èÖµR=4000¦¸£¬
ÓÉ´®Áªµç·Ìص㼰±ÕºÏµç·ŷķ¶¨Âɵãº
  E=I1£¨R+RÄÚ£©£¬
¼´9.0V=0.002A¡Á£¨4000¦¸+RÄÚ£©£¬
½âµÃRÄÚ=500¦¸£®ÔòAÕýÈ·£»
B¡¢µ±µçÁ÷I2=0.0036Aʱ£¬ÓÉ´®Áªµç·Ìص㼰ŷķ¶¨Âɵãº
  EU=I2£¨R¡ä+RÄÚ£©
¼´£º9.0V=0.0036A¡Á£¨R¡ä+500¦¸£©£¬
½âµÃ£ºR¡ä=2000¦¸£»
ÓÉͼÏóÖª£¬´ËʱÈÈÃôµç×èµÄζÈt=100¡æ£®ÔòBÕýÈ·£»
C¡¢Î¶ÈÉý¸ß£¬µç×è±äС£¬Ôò±ÈÖµ±äС£¬ÔòC´íÎó£»
D¡¢ÓÉU=E-Ir  Ôò$\frac{¡÷U}{¡÷I}$=r£¬Ôò²»±ä£¬ÔòD´íÎó£®
¹ÊÑ¡£ºAB£®

µãÆÀ ±¾Ì⿼²éÁË´®Áªµç·µÄÌص㡢ŷķ¶¨ÂÉ¡¢Ê¶Í¼ÄÜÁ¦£¬ÊìÁ·ÕÆÎÕ´®Áªµç·µÄÌص㡢ŷķ¶¨ÂÉÊÇÕýÈ·½âÌâµÄÇ°ÌᣬÓÉͼÏóÕÒ³öÈÈÃôµç×èµÄ×èÖµÓë¶ÔÓ¦µÄζȹØϵÊǽâÌâµÄ¹Ø¼ü£»½âÌâʱעÒⵥλ»»Ë㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø