题目内容
如图,圆柱形气缸的上部有小挡板,可以阻止活塞滑离气缸,气缸内部的高度为d,质量不计的薄活塞将一定质量的气体封闭在气缸内.开始时活塞离底部高度为
,温度为t1=27℃,外界大气压强为p0=1atm,现对气体缓缓加热.求:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241345120321617.png)
(1)气体温度升高到t2=127℃时,活塞离底部的高度;
(2)气体温度升高到t3=357℃时,缸内气体的压强;
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512001485.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241345120321617.png)
(1)气体温度升高到t2=127℃时,活塞离底部的高度;
(2)气体温度升高到t3=357℃时,缸内气体的压强;
(1)
(2)p=1.4atm
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512110686.png)
(1)由题意得V1=
,T1=273+27=300k,V2=Sh2,T2=127+273=400k,由盖吕萨克定律
(2分)得:
(1分)
(2)由题意得V1=
,T1=273+27=300k,V3=Sd,活塞刚好到达顶部时气体温度为T3,由盖吕萨克定律
得T3=450K(2分)
当温度升到T4=357+273=630K,由查理定律![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512578169.png)
(2分)得p=1.4atm(1分)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512360587.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512407628.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512110686.png)
(2)由题意得V1=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512360587.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512532636.png)
当温度升到T4=357+273=630K,由查理定律
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512578169.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134512656674.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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