题目内容
如图6-2-15所示,一根足够长的水平滑杆SS′上套有一质量为m的光滑金属圆环.在滑杆的正下方与其平行放置一足够长的光滑水平的木质轨道,且穿过金属球的圆心O,现使质量为M的条形磁铁以v0的水平速度沿轨道向右运动,则( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241136095362606.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241136095362606.gif)
A.磁铁穿过金属环后,二者将先后停下来 |
B.圆环可能获得的最大速度为![]() |
C.磁铁与圆环系统损失的动能可能为Mmv02/2(M+m) |
D.磁铁与圆环系统损失的动能可能为![]() |
BC
整个过程中,二者组成系统总动量守恒,且发生动能向电能再向内能的转化.由动量守恒定律Mv0=(M+m)v,v=
,又由能量关系:Q=ΔE损=
mv02-
(M+m)v2=![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113609801642.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113609583595.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113609567225.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113609567225.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824113609801642.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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