题目内容
如图, 半径为
和
的圆柱体靠摩擦传动,已知
,
分别在小圆柱与大圆柱的边缘上,
是圆柱体上的一点,
,如图所示,若两圆柱之间没有打滑现象,则
∶
∶
=" ———————" ;ωA∶ωB∶ωc= —————————— 。
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250044277273334.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427555260.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427571303.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427587463.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427602419.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427633306.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427649514.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427680351.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427696350.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427711339.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250044277273334.png)
2:2:1 ; 2:1:1
试题分析:传动过程中,两圆柱之间没有打滑现象,说明A、B两点的线速度相等,即vA=vB,根据v=ωr,有ωA:ωB=2:1;B、C绕同一个轴转动,角速度相等,根据ω=
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825004427743364.png)
所以vA:vB:vC=2:2:1; ωA:ωB:ωC=2:1:1;
![](http://thumb2018.1010pic.com/images/loading.gif)
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