题目内容
如图所示,光滑球质量m,在图甲中是细线与斜面平行,图乙中是细线沿水平方向,小球均是静止状态,则甲、乙两种情况下,斜面对小球的支持力之比为( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250022237848164.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250022237848164.png)
A.1:1 | B.cos2![]() | C.1:cos2![]() | D.sin![]() ![]() |
B
试题分析:对甲和乙分别受力分析,并将重力按照作用效果分解如图:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250022238789828.png)
由受力平衡可知,
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250022238931083.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825002223909796.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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A.1:1 | B.cos2![]() | C.1:cos2![]() | D.sin![]() ![]() |