题目内容
(10分)如图所示的电路中,两平行金属板A、B水平放置,两板间的距离
,电源电动势
,内电阻
,电阻
,闭合开关S,待电路稳定后,一带电量
C, 质量
的小球恰好静止于两板之间。取
,求:
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/201408250030575403452.jpg)
(1)两板间的电压为多少
(2)此时,滑动变阻器接入电路的阻值为多少
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057399573.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057415552.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057430445.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057446512.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057462558.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057493732.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057508619.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/201408250030575403452.jpg)
(1)两板间的电压为多少
(2)此时,滑动变阻器接入电路的阻值为多少
8V 8![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057555333.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057555333.png)
试题分析:由题意可知小球恰好静止于两板之间,一小球为对象,受到重力和电场力二力平衡,所以有
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057571758.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/201408250030575861477.png)
设此时滑动变阻器接入电路的阻值为RP,由闭合电路欧姆定律可得电路中的电流为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057602733.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057618516.png)
得:
![](http://thumb.zyjl.cn/pic2/upload/papers/20140825/20140825003057633565.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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