ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬Á½¸öͬÐÄÔ²,°ë¾¶·Ö±ðΪrºÍ2r,ÔÚÁ½Ô²Ö®¼äµÄ»·ÐÎÇøÓòÄÚ´æÔÚ´¹Ö±Ö½ÃæÏòÀïµÄÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶ÈΪB¡£Ô²ÐÄO´¦ÓÐÒ»·ÅÉäÔ´,·Å³öÁ£×ÓµÄÖÊÁ¿Îªm,´øµçÁ¿Îªq,¼ÙÉèÁ£×ÓËٶȷ½Ïò¶¼ºÍÖ½ÃæƽÐС££¨1£©Í¼ÖмýÍ·±íʾijһÁ£×Ó³õËٶȵķ½Ïò£¬OAÓë³õËٶȷ½Ïò¼Ð½ÇΪ60¡ã£¬ÒªÏëʹ¸ÃÁ£×Ó¾¹ý´Å³¡µÚÒ»´Îͨ¹ýAµã£¬Ôò³õËٶȵĴóСÊǶàÉÙ£¿
£¨2£©ÒªÊ¹Á£×Ó²»´©³ö»·ÐÎÇøÓò£¬ÔòÁ£×ӵijõËٶȲ»Äܳ¬¹ý¶àÉÙ?
£¨1£©ÈçͼËùʾ£¬ÉèÁ£×ÓÔڴų¡ÖеĹìµÀ°ë¾¶ÎªR1£¬ÔòÓɼ¸ºÎ¹ØϵµÃ R1= ÓÉq1B=mµÃ1= £¨2£©ÉèÁ£×ÓÔڴų¡ÖеĹìµÀ°ë¾¶ÎªR2£¬ÔòÓɼ¸ºÎ¹Øϵ£¨2r- R2£©2= R22+ r2 µÃR2=3r/4 ÓÉq2B=m µÃ2=
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿