题目内容
(14分)如图12所示,电源电动势E=12 V,内阻r=1 Ω,电阻R1=3 Ω,R2=2 Ω,R3=5 Ω,电容器的电容C1=4 μF,C2=1 μF,求C1、C2所带电荷量.![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241415069403936.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241415069403936.png)
1.6×10-5 C 10-5 C
根据闭合电路欧姆定律,
I=
=
A=2 A,
U1=IR1=6 V,U2=IR2=4 V
UC1=U2=4 V,UC2=U1+U2=10 V
根据Q=CU
Q1=C1UC1=4×10-6×4 C=1.6×10-5 C
Q2=C2UC2=1×10-6×10 C=10-5 C.
I=
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824141507018682.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824141507081442.png)
U1=IR1=6 V,U2=IR2=4 V
UC1=U2=4 V,UC2=U1+U2=10 V
根据Q=CU
Q1=C1UC1=4×10-6×4 C=1.6×10-5 C
Q2=C2UC2=1×10-6×10 C=10-5 C.
![](http://thumb2018.1010pic.com/images/loading.gif)
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